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Amiraneli [1.4K]
3 years ago
8

If sin 0=7/25, use the Pythagorean identity to find cos 0

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0
3+x=23t therefore the answer should be D


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Triangle ABC has vertices A(–1, 0), B(4, 0), and C(2, 6). If ΔABC is translated using the function rule (x, y) → (x – 6, y – 5)
Elina [12.6K]

Answer:

b.  A''(7, 5), B''(2, 5), C''(4, –1)

Step-by-step explanation:

Given vertices of ΔABC:

  • A = (-1, 0)
  • B = (4, 0)
  • C = (2, 6)

Translation <u>mapping rule</u>:

(x, y) → (x – 6, y – 5)

Therefore:

  • A' = (-1 - 6, 0 - 5) = (-7, -5)
  • B' = (4 - 6, 0 - 5) = (-2, -5)
  • C' = (2 - 6, 6 - 5) = (-4, 1)

Rotation of 180° clockwise rule:

(x, y) → (-x, -y)

Therefore:

  • A'' = (-7, -5) = (7, 5)
  • B'' = (-2, -5) = (2, 5)
  • C'' = (-4, 1) = (4, -1)

Learn more about transformations here:

brainly.com/question/28354239

brainly.com/question/27743837

5 0
1 year ago
Help me with part e please.​
Andru [333]
I believe it would be 98
3 0
3 years ago
What is the greatest common factor of 3x4, 15x3, and 21x??
luda_lava [24]

Answer:

The GCF of 3x^4, 15x^3 and 21x is 3x^2

Step-by-step explanation:

3x^2(x^2), 3x^2(5x) , 3x^2(7)

4 0
3 years ago
Read 2 more answers
A stadium has a seating capacity of 65,000 spectators.
Montano1993 [528]
X = capacity

64999 < x <  \ 65001
3 0
3 years ago
With a little care, you can find the median and the quartiles from the histogram. what are these numbers? you can also find the
coldgirl [10]

Complete Question

The histogram from this question is shown on the first uploaded image

Answer:

The first quartile is  1st Q = 19^{th} girl (subject ) = 1 \serving\ of\ fruit\ per\ day

The median is   Median  = 38 ^{th} \ girl (subject) =  2 \serving\ of\ fruit\ per\ day

The third quartile  is 3rd Q =  56^{th} \  girl (subject) = 4 \serving\ of\ fruit\ per\ day  

The  mean is  \= x = 2.62

Step-by-step explanation:

From the question we are told that

   The total  number of girls is n =  74

Generally the median is mathematically represented as

       Median  =  \frac{\frac{n}{2}  +[ \frac{n}{2} + 1]  }{2}

So

          Median  =  \frac{\frac{74}{2}  +[ \frac{74}{2} + 1]  }{2}

=>         Median  =  \frac{37  +38 }{2}

=>         Median  =37.5 \  girl    

From the histogram 37.5 \approx 38^{th} \ girl fall under 2 fruits per day

Generally the first quartile is mathematically represented as

      1st \ Q =  \frac{\frac{n}{4} + [\frac{n}{4} + 1]  }{2}

=>    1st \ Q =  \frac{\frac{74}{4} + [\frac{74}{4} + 1]  }{2}

=>     1st \ Q = 19 \  girl

From the histogram 19^{th}girl fall under 1 fruit per day

 Generally the third quartile is mathematically represented as

     3rd\  Q =  \frac{\frac{n}{2}  + n }{2}

=>    3rd\  Q =  \frac{\frac{74}{2}  + 74 }{2}

=>    3rd\  Q =  55.5

From the histogram 55.5 \approx 56^{th} \ girl fall under 4 fruits per day

Generally from the histogram table the frequency  [number of subjects (girls) ]  and the servings of fruit per day can be represented as

                                                                                                               Total

x(servings per day )        0     1     2     3     4     5    6     7      8    

f (number of subjects )   15    11   15     11    8     5    3     3      3    \sum f  =  74

xf                                       0    11    30   33   32  25   18   21     24    \sum xf =  194

Generally the mean is mathematically represented as

      \= x = \frac{1}{ \sum f}  * [\sum xf]

=>     \= x = \frac{1}{ 74}  *194

=>      \= x = 2.62

4 0
3 years ago
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