<span>a+b) • (a2-ab+b2)
</span><span>(a+b) • (a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+<span>b<span>3
ANWSER </span></span></span><span> y4 - y3 + 2y2 + y - 1
——————————————————————
(y + 1) • (y2 - y + 1)</span>
Answer:
(2,0)
Step-by-step explanation:
For given line AB:
y-intercept = b = -2
slope = m = y₂-y₁/x₂-x₁
= -3/2-(-4) = -3/6 = -1/2
Equation of line AB:
y = (-1/2)x - 2
Finding equation of line that is parallel to line AB and passes through the point C(2,2):
Substituting the slope from line AB into the equation of the line
y = (-1/2)x + b.
Substituting the given point (-2,2) into the x and y values 2 = (-1/2)-2 + b.
Solving for b (the y-intercept)
, we get b = 1
Substitute this value for 'b' in the slope intercept form equation y = (-1/2)x + 1.
For x-intercept of the line, we let y = 0
0 = (-1/2)x + 1
x = -1(-2/1)
x = +2
So, the point on the x-axis that lies on the line that passes
through point C and is parallel to line AB is (2,0).
The answer is r<6
yycjj. hgxs tfdg
This can be solve by using the average cans of each student
collected and muliply it by the total students. Since for ms. Lee has 24
students and each student collected 18 cans on average, so the total can her
class collected on average is 432 cans. For mr galveshas 21 students and
collected 25 can per syudents on average, so the total is 525 cans. So 525 –
432 = 93 more cans the class of mr galvez collected
