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2 years ago

Simplify : 48÷6 [-52 ÷2 {4 - 3 (2 - 15÷3)}]

Mathematics

1 answer:

garri49 [273]2 years ago

8 0

Answer:

Step-by-step explanation:

$48÷6 [-52 ÷2 {4 - 3 (2 - 15÷3)}] \\ 8[-52 ÷2 {4 - 3 (2 - 15÷3)}] \\ 8[-52 ÷2{1 (2 - 15÷3)}] \\ 8[ - 2.5{ (2 - 15÷3)}] \\ 8[ - 2.5{ ( - 13÷3)}] \\ 8[ - 2.5{ ( - 4.3)}] \\ 8[10.75 { }] \\ = 86$

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olchik [2.2K]

Answer:

f(-4) = -2

Step-by-step explanation:

To find f(-4) use the "piece" of the function rule defined for x < -3 (because -4 is less than -3). That part of the rule says the output (range) value is x + 2, so f(-4) = -4 + 2 = -2.

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2 years ago

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3 years ago

Mr. Zelman wants to give 50% of his comic book collection to his nephew Alex. If Mr. Zelman has 800 comic books, then how many w

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Mr. Zelman gave 400 books to his nephew

Solution:

Given that, Mr. Zelman wants to give 50% of his comic book collection to his nephew Alex

Mr. Zelman has 800 comic books

Number of books with Zelman = 800

Mr. Zelman wants to give 50% of books to Alex

Number of books given to nephew = 50 % of books of Zelman

Therefore, we have to find 50 % of 800

$\rightarrow 50 \% \text{ of } 800$

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Thus he gave 400 books to his nephew

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3 years ago

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3 years ago

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Ivan used coordinate geometry to prove that quadrilateral EFGH is a square.

Gelneren [198K]

Answer:

(A)Segment EF, segment FG, segment GH, and segment EH are congruent

Step-by-step explanation:

Step 1

Quadrilateral EFGH with points E(-2,3), F(1,6), G(4,3), H(1,0)

Step 2

Using the distance formula

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given E(-2,3), F(1,6)

$|EF|=\sqrt{(6-3)^2+(1-(-2))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given F(1,6), G(4,3)

$|FG|=\sqrt{(3-6)^2+(4-1)^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}$

Given G(4,3), H(1,0)

$|GH|=\sqrt{(0-3)^2+(1-4)^2}=\sqrt{(-3)^2+(-3)^2}=\sqrt{18}=3\sqrt{2}$

Given E (−2, 3), H (1, 0)

$|EH|=\sqrt{(0-3)^2+(1-(-2))^2}=\sqrt{(-3)^2+(3)^2}=\sqrt{18}=3\sqrt{2}$

Step 3

Segment EF ,E (−2, 3), F (1, 6)

Slope of |EF|= $\frac{6-3}{1+2} =\frac{3}{3}=1$

Segment GH, G (4, 3), H (1, 0)

Slope of |GH| $= \frac{0-3}{1-4} =\frac{-3}{-3}=1$

Step 4

Segment EH, E(−2, 3), H (1, 0)

Slope of |EH| $= \frac{0-3}{1+2} =\frac{-3}{3}=-1$

Segment FG, F (1, 6,) G (4, 3)

Slope of |EH| $=\frac{3-6}{4-1} =\frac{-3}{3}=-1$

Step 5

Segment EF and segment GH are perpendicular to segment FG.

The slope of segment EF and segment GH is 1. The slope of segment FG is −1.

Step 6

Segment EF, segment FG, segment GH, and segment EH are congruent.

The slope of segment FG and segment EH is −1. The slope of segment GH is 1.

Step 7

All sides are congruent, opposite sides are parallel, and adjacent sides are perpendicular. Quadrilateral EFGH is a square

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3 years ago

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Simplify : 48÷6 [-52 ÷2 {4 - 3 (2 - 15÷3)}]​

Simplify : 48÷6 [-52 ÷2 {4 - 3 (2 - 15÷3)}]