Answer: Hello!
Here you have 53 integrated circuits, each with a probability of 0.02 of being defective.
If only one of them is defective, then the electronic product doesnt work.
Then we need the calculate the probability in wich all the 53 circuits arent defective.
the probability for each one to not be defective is 1 - 0.02 = 0.98
And if i want to see the probability for all of them to work fine, then i need to do the product of all the probabilities, this is multiply 0.98 53 times, or:
rounding to the four decimal place, we have: 0.3428
Wich is a kinda small probability for our product to work.
Using the identity sin^2(t)+cos^2(t)=1
and
given sin(t)=0.3,
we can find cos(t) by substituting
sin^2(t)+cos^2(t)=1
0.3^2+cos^2(t) = 1
cos^2(t)=1-0.3^2=1-0.09=0.91
cos(t)=sqrt(0.91)= 0.954 ≠ 0.6
So the given proposition is false.
Answer:
Step-by-step explanation: To calculate the percentage, multiply this fraction by 100 and add a percent sign. 100 * numerator / denominator = percentage . In our example it's 100 * 2/5 = 100 * 0.4 = 40 .