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3 years ago

What does cpctc represent and when would you use it

Mathematics

2 answers:

faltersainse [42]3 years ago

6 0

CPCTC represents<span> is a succinct statement of a theorem regarding </span>congruent trigonometry<span>, defined as triangles either of which is an </span>isometry of the other. <span>CPCTC states that if two or more triangles are congruent, then all of their corresponding angles and sides are congruent as well. CPCTC is useful in proving various theorems about triangles and other polygons.</span>

sergejj [24]3 years ago

4 0

Answer: Corresponding parts of congruent triangles are congruent.

Step-by-step explanation:

This states that if the two sides/angles of a triangle are congruent,all other sides are also going to be congruent. It is a theorem for mainly trigonometry. According to the image attached any two congruent angles in any of the triangle will be congruent with the corresponding sides in the other triangle. It is used mainly in construction to re-enforce pillars and other structures.

angle POR=LMN if any of them is congruent according to the attached picture.

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Answer:

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I hope this helps if not check out Khan academy

https://www.khanacademy.org/math/algebra/introduction-to-algebra/alg1-dependent-independent/v/dependent-and-independent-variables-exercise-example-3

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Nikitich [7]

The possible form of the point (6√3, - 6) in polar form are (r₁, θ₁) = (12, 11π / 6), (r₂, θ₂) = (12, - π / 6).

<h3>How to derive the polar form of a point in rectangular form</h3>

In this problem we find a point in rectangular form, that is, a point of the form (x, y). We are asked to find the polar form of the point, that is, a point described by the following expression:

(r, θ)

Where:

r - Magnitude
θ - Direction, in radians

The magnitude is found by Pythagorean theorem:

r =√(x² + y²)

And the direction of the point is described by the following inverse trigonometric function:

θ = tan⁻¹ (y / x)

If we know that (x, y) = (6√3, - 6), then the point in polar form is:

r = √[(6√3)² + (- 6)²]

r = 12

θ = tan⁻¹ (- 6 / 6√3)

θ = tan⁻¹ (- √3 / 3)

θ = 11π / 6 rad / θ = - π / 6 rad

There are two possible solutions: (r₁, θ₁) = (12, 11π / 6), (r₂, θ₂) = (12, - π / 6).

To learn more on point in polar form: brainly.com/question/13103661

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