Answer:
the answer is d.
Step-by-step explanation:
first, you want to use the formula,
new value - original value
<u>____________________</u>
original value * 100
you see that 84 is the new value and 79 would be the original value. substitute the numbers in. this is a increase since you will get a positive value.
84 - 79
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79 * 100
now we solve it.
5
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79 * 100
you can either solve the fraction first then multiply that by 100 or multiply the numerator by 100 first then divide that by 79, each way works.
500
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79 = approximately 6.3% increase (this is not a exact value, just rounded)
or
5
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79 = approximately 0.063 (this is not a exact value, just rounded)
0.063 * 100 = 6.3% increase
Equation~ 5b + (2b - 4) + (3b -6)= 180.
so, we have two 54x18 rectangles, so their perimeter is simply all those units added together, 54+54+54+54+18+18+18+18 = 288.
we know the circle's diameter is 1.5 times the width, well, the width is 18, so the diameter of the circle must be 1.5*18 = 27.
![\bf \stackrel{\textit{circumference of a circle}}{C=d\pi }~~ \begin{cases} d=diameter\\[-0.5em] \hrulefill\\ d=27 \end{cases}\implies C=27\pi \implies C=\stackrel{\pi =3.14}{84.78} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{perimeter of the rectangles}}{288}~~~~+~~~~\stackrel{\textit{perimeter of the circle}}{84.78}~~~~=~~~~372.78](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bcircumference%20of%20a%20circle%7D%7D%7BC%3Dd%5Cpi%20%7D~~%20%5Cbegin%7Bcases%7D%20d%3Ddiameter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20d%3D27%20%5Cend%7Bcases%7D%5Cimplies%20C%3D27%5Cpi%20%5Cimplies%20C%3D%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B84.78%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20rectangles%7D%7D%7B288%7D~~~~%2B~~~~%5Cstackrel%7B%5Ctextit%7Bperimeter%20of%20the%20circle%7D%7D%7B84.78%7D~~~~%3D~~~~372.78)
Selection D is the equivalent form of the given expression.
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The nominal annual interest rate in this problem is 40%. If it were compounded half-yearly, the formula would be x(1.2)^(2t) or x(1.44)^t. Apparently, this problem is more concerned with the equivalent form of the expression than it is with half-yearly compounding.
Don’t know sorry I need point
