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amm1812
3 years ago
5

Of the following mumbers,which one is prime 14,13,21,33

Mathematics
2 answers:
vfiekz [6]3 years ago
4 0
The prime number is 13
timofeeve [1]3 years ago
4 0
This is easy. 

The answer is: 13. 

Explanation:

A prime number is a number that is only divisible by one and itself. 
Let's list their divisors. 

14: 1,2,7,14
13:1,13
21: 1,3,7,21
33: 1, 3, 11, 33

We can see that 13 is the only one that is divisible by 1 and itself.
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Which of the following transformations preserves orientation, but does NOT preserve congruence?
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Reflection does not preserve orientation.
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3 years ago
I don't understand this
mars1129 [50]
The GCF is 7!!:))))))
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A trapezoid has base lengths of 36cm and 60cm. the area is 768^2. Find the height.
Harlamova29_29 [7]

Answer:

if you mean 768 centimeters squared then the height is 16.38 cm. but just in case, if you did mean 768 squared then the height is 12288.21.

Step-by-step explanation:

5 0
3 years ago
Simplify. pls pls pls helppp im really bad at math lol<br> a) 6 √3+ 4<br> b) 6 √6+ 3<br> c) 4 √3 + 6
Mandarinka [93]
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5 0
3 years ago
Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They
ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

P = 2

G = 3

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)

This gives:

P(G_1\ and\ G_2) = P(G_1) * P(G_2)

P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}

P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}

P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}

P(G_1\ and\ G_2) = \frac{3}{10}

P(P_1\ and\ P_2) = P(P_1) * P(P_2)

P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}

P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}

P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}

P(P_1\ and\ P_2) = \frac{1}{10}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)

P(Same) = \frac{3}{10} + \frac{1}{10}

P(Same) = \frac{3+1}{10}

P(Same) = \frac{4}{10}

P(Same) = \frac{2}{5}

8 0
3 years ago
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