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alina1380 [7]
3 years ago
7

A culture of bacteria grows in a lab according to the model B = 600e^(kt) where t is the measured in hours. The culture reaches

a size of 750 after 6 hours. Find the value of k.
NO LINKS!!!!!!
Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0

9514 1404 393

Answer:

  k ≈ 0.03719

Step-by-step explanation:

Fill in the given numbers and solve for k.

  750 = 600e^(6k)

  1.25 = e^(6k)

  ln(1.25) = 6k . . . . . take the natural log

  k = ln(1.25)/6 . . . . . divide by 6

  k ≈ 0.03719

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Answer:

B

Step-by-step explanation:

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Which of the following would not be a correct interpretation of a correlation of r = .35?
Nikitich [7]
Even though it may look like the option is E the real answer is that the variables are invesely related. So your answer will be D
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How many ways can we pick three distinct integers from {1, 2, ..., 15} such that their sum is divisible by 3?
gogolik [260]

Answer:

Clearly from 1 to 15 we can only have the sum 6,9,12 and 15 to be divisible by 3.

Now meaning we have 4! ( 4 factorial) which implies 4x3x2x1= 24 .

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Step-by-step explanation:

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3 years ago
There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one
diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0
4 years ago
In FGH, the measure of H=90°, HF=91 feet, and GH = 50 feet. Find the measure of F to the nearest degree.
Rudik [331]

Given:

The angle of H=90°, HF=91 feet, and GH = 50 feet.

The objective is to find the measure of angle<em> F.</em>

In the given right angled triangle, the side opposite to the requierd angle is called opposite side, and the other smaller side is called adjacent side.

The trigonometry formula which relates with the opposite and adjacent side is,

\tan \theta=\frac{opposite}{adjacent}

Now substitute the value of opposite and adjacent in the above formula to find the value of angle <em>F</em>.

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Hence, the value of angle <em>F</em> is 29 degree.

3 0
1 year ago
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