<span>1. Solve the system by substitution -2x+y=-11, 3x-4y=11.
</span>-2x+y=-11<span>
y = 2x-11
</span><span>3x-4y=11
</span>3x-4(2x-11)=11
3x -8x + 44 = 11
-5x = -33
<span>x =33/5
y = 11/5
</span><span>2. Solve the system using elimination- 2x+6y=-12, 5x-5y=10.
</span><span>(-2x+6y=-12)5
</span>-10x + 30y = -60
<span>(5x-5y=10)2
</span>10x - 10y = 20
Adding the two equations,
<span>-10x + 30y = -60
</span><span>10x - 10y = 20
</span>
20y = -40
y = -2
x = 0
<span>3. What is the solution of the following system?-3x-2y=-12, 9x+6y=-9.
</span><span>-3x-2y=-12
</span>y = -3/2 x + 6
<span>9x+6y=-9
</span>y = -3/2 x - 3/2
Since the slopes are equal then they are parallel lines so they never meet at one point.
It’s the second one, cause 6%=.06 and in the parentheses 1+.06=1.06.
Answer:
(–10, –2), (6, 6)
Step-by-step explanation:
we know that
The formula to calculate the slope between two points is equal to
<u><em>Verify each case</em></u>
case 1) (5, –4), (–2, 1)
substitute in the formula
----> the slope is negative
case 2) (6, –10), (2, 10)
substitute in the formula
----> the slope is negative
case 3) (–10, –2), (6, 6)
substitute in the formula
----> the slope is positive
case 4) (5, –1), (–6, 6)
substitute in the formula
----> the slope is negative
Answer:
√10
Step-by-step explanation:
√(x2-x1)^2+(y2-y1)^2=√10
