The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is

Dividing we get,

Adding, we have,

Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,

where
and 
Hence, substituting the values we have,

Dividing, we get,

Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
increase
Step-by-step explanation:
the number got bigger
Answer:
b=30
Step-by-step explanation:
The angle here is a right angle which is an angle that equals 90 degrees. You subtract that measure of the angle by 60 and you end up with 30.
Answer:
(7, 3)
Step-by-step explanation:
Using the midpoint formula
M(X, Y) = {(ax1+bx2/a+b), ay1+by2/a+b}
X = ax1+bx2/a+b
X = -5(1)+3(11)/1+3
X = -5+33/4
X = 28/4
X = 7
Y = ay1+by2/a+b
Y = 1(12)+3(0)/1+3
Y = 12/4
Y = 3
Hence the coordinate of P is at (7, 3)