Answer:
The circumference of the circle is 
.
Step-by-step explanation:
A sector is the part of a circle enclosed by two radii of a circle and their intercepted arc. A pie-shaped part of a circle.
The area of a circle is given by 
The formula used to calculate the area of a sector of a circle is:
The circumference of a circle is the distance around the outside of the circle and its given by
We know the central angle 
= 110º and the area of the sector 50 units squared.
First, we use the formula to calculate the area of a sector to find the radius.
The radius can't be negative. Therefore,
Next, we apply the formula for the circumference of a circle.
multiply and add then subtract. steps are in the picture.
D is the answer as the both have solution x=-2 y=3
14x=-28 12(-2)-3y=-33
x=-2 -3y=-9
y=3
from the given equation
4x-y=11 eq 1
2x+3y=5 eq 2
x=y-11/4 from equation 1
subsitute this value of x in equation 2
2(y-11/4)+3y=5
y-11+6y=10
7y-11=10
y=3
subsitude this value of y in equation (x=y-11/4)
so x= -2
thus same solution so ANSWER IS D
Answer:
all real numbers except ±5.
Step-by-step explanation:
Each function (f(x), g(x)) has a domain that is all real numbers. Their quotient (f(x)/g(x)) must exclude values that make g(x) = 0. The quotient is undefined when the denominator is zero. Those excluded values are x = ±5.
The domain of (f/g)(x) is all real numbers except ±5.
___
Of course you recognize x^2 -25 = 0 has solutions x = ±√25 = ±5. You can get there two ways:
- add 25 and take the square root: x^2=25; x=±√25.
- factor the difference of squares and set the factors to zero: (x-5)(x+5)=0 has solutions x-5=0 and x+5=0, that is, x = ±5.
= x^2 - y^2/6 * 12/(x-y)
= 6x^2 -y^2 * 72/(x-y)
= 6x^2(x-y) -y^2(x-y) * 72
= 6x^3 - 18x^2 -xy^2 + y^3 * 72
= 432x^3 - 1296x^2 -72xy^2 + 72y^3
