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noname [10]
3 years ago
12

Simplify 2x + 5(2x - 3)

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Step-by-step explanation:

= 2x + 10x - 15

=12x - 15

I think this is the answer

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zubka84 [21]

The HCF are

  • 3
  • 6
  • 3
  • 12
  • 6
  • 18
  • 8
  • 14
  • 15

<h3>What is HCF?</h3>

This is the common factor that is the highest that a group of numbers can have in common.

1. 6 and 15

factors of 6 =  1, 2, 3, 6

factors of 15:  1, 3, 5, 15

The HCF is the number they have in common = 3

2. 12 and 18

The factors of 12:  1, 2, 3, 4, 6, 12

The factors of 18:  1, 2, 3, 6, 9, 18

The HCF = 6

3. 15 and 24

Factors of 15:  1, 3, 5, 15

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

The HCF = 3

4. 24 and 36

The factors of 24:  1, 2, 3, 4, 6, 8, 12, 24

The factors of 36:  1, 2, 3, 4, 6, 9, 12, 18, 36

The HCF :  12

5. 30 and 48

The factors of 30:  1, 2, 3, 5, 6, 10, 15, 30

The factors of 48:  1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The HCF = 6

6. 36 and 54

The factors of 36:  1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 54:  1, 2, 3, 6, 9, 18, 27, 54

The hcf = 18

7. 32,40 and 56

The factors of 32:  1, 2, 4, 8, 16, 32

The factors of 40:  1, 2, 4, 5, 8, 10, 20, 40

The factors of 56:  1, 2, 4, 7, 8, 14, 28, 56

The HCF is 8

8. 28,42 and 70

The factors of 28:  1, 2, 4, 7, 14, 28

The factors of 42:  1, 2, 3, 6, 7, 14, 21, 42

The factors of 70:  1, 2, 5, 7, 10, 14, 35, 70

The HCF = 14

9. 30,75 and 90

The factors of 30:  1, 2, 3, 5, 6, 10, 15, 30

The factors of 75:  1, 3, 5, 15, 25, 75

The factors of 90:  1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

The HCF is 15

Read more on HCF here;

brainly.com/question/21504246

#SPJ1

8 0
2 years ago
Evaluate 13 + 6/y when y = 6
DIA [1.3K]

Answer: 14

Step-by-step explanation: According to PEMDAS you do division first so if y=6 then you do 6/6=1. Then add 13+1

4 0
3 years ago
Read 2 more answers
6. Camille is a first year accountant and a recent college graduate. She is paid a salary
Marina CMI [18]

jk ima awnser in one sec

4 0
3 years ago
A civil engineer is analyzing the compressive strength of concrete. Compressive strength is normally distributed with σ = 31.62
AysviL [449]

Answer:

A sample size of at least 737 specimens is required.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the width M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

M = 3, \sigma = 31.62

So:

M = z*\frac{\sigma}{\sqrt{n}}

3 = 2.575*\frac{31.62}{\sqrt{n}}

3\sqrt{n} = 81.4215

\sqrt{n} = 27.1405

n = 736.60

A sample size of at least 737 specimens is required.

6 0
4 years ago
(b) Find z such that 39% of all observations from a standard normal distribution are greater than z. (Enter your answer rounded
vova2212 [387]

For 39% of all observations that are greater than z on the normal distribution table, the percentage of observations that are lesser than z is

100 - 39 = 61%

The proportion is 61/100 = 0.61

From the normal distribution table, the value of z corresponding to this proportion is 0.28

Thus, the required value of z is 0.28

3 0
1 year ago
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