The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π
<h3>The circle with center P</h3>
Given that the circle has a center P
It means that lengths PQ, PR, PS and PT
From the question, we understand that QR = ST.
This implies that triangles QRP and STP are congruent.
i.e. △QRP ≅ △STP is true
<h3>The length of the minor arc</h3>
The given parameters are:
Angle, Ф = 99
Radius, r = 1
The length of the arc is:
L = Ф/360 * 2πr
So, we have:
L = 99/360 * 2π * 1
Evaluate
L = 198/360π
Divide
L = 11/20π
Hence, the length of the minor arc is 11/20π
Read more about circle and arcs at:
brainly.com/question/3652658
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The line passes through two points that have the same x-coordinate.
It is a vertical line. To find the slope of a line, use any two points. Subtract the y-coordinates. Subtract the x-coordinates in the same order. Then divide the difference of the y-coordinates by the difference of the x-coordinates. Since in this case, the x-coordinates are both -6, the difference between the x-coordinates is zero. Division by zero is not defined, so the slope of this line is undefined. You can't write its equation in point-slope form, because there is no slope for this line.
Answer:
(3n - 8)(2n + 5)
Step-by-step explanation:
6n² - n - 40
Consider the factors of the product of the coefficient of the n² term and the constant term which sum to give the coefficient of the n- term
product = 6 × - 40 = - 240 and sum = - 1
The factors are - 16 and + 15
Use these factors to split the n- term
6n² - 16n + 15n - 40 ( factor the first/second and third/fourth terms )
2n(3n - 8) + 5(3n - 8) ← factor out (3n - 8) from each term
(3n - 8)(2n + 5)
Then
6n² - n - 40 = (3n - 8)(2n + 5)
Answer:
The solutions are π/4, 3π/4,5π/4,7π/4
Step-by-step explanation:
The given equation is
6sin²(x) = 3
Divide by 6 to get:
This implies that;
If
in the first quadrant
in the second quadrant.
If
in the third quadrant
