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3 years ago

Could you guys please solve these equations?

Mathematics

1 answer:

Andrej [43]3 years ago

8 0

Answer:

x = 4

b = 7

n = 40

I hope this helps!!!

Step-by-step explanation:

1) 12x-17 = 6x+7

+17 +17

*do this because you want to get all of the variables to one side and all of the constants to one side*

12x = 6x + 24

-6x -6x

6x = 24

*divide by 6 to get x alone, so you 24/6 = 4*

x = 4

2) -8b+1 = -5(b+4)

*must multiply -5 by everything in the parenthesises*

-8b+1 = -5b-20

-1 -1

-8b= -5b-21

+5b +5b

-3b = -21

b = 7

3) 350+10(n-7) = 630+2(n-15)

350+10n-70 = 630+2n-30

*combine like terms on both sides of the equation*

280+10n = 600+2n

-280 -280

10n = 320+2n

-2n -2n

8n = 320

n = 40

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Is a triangle with the three sides being 24 22 and 26 a right triangle?

Vilka [71]

No because 22 squared plus 24 squared does not = 26 squared

7 0

3 years ago

Given a polynomial f(x), if (x − 4) is a factor, what else must be true?

ollegr [7]

Answer:

$f(4)=0$

Step-by-step explanation:

The Remainder Theorem states that when you divide a polynomial $f(x)$ by a linear factor $(x-a)$ , where $a$ is a constant, the remainder is $f(x)$ evaluated at $x=a$

Moreover, according to the Factor Theorem, an extension of the Remainder Theorem, if the remainder of the function $f(x)$ is 0 when evaluated at $x=a$ , then $(x-a)$ is said to be a factor of the polynomial $f(x)$

Given the 2 theorems above, it follows that if $(x-4)$ is a factor of $f(x)$ , then the remainder is equal to 0 when $f(x)$ is evaluated at $x=4$