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Lana71 [14]
3 years ago
10

Math question pls help

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0

Answer:

y = x + 3

Step-by-step explanation:

This is because the number is increasing by three each time and if you substituted the variable x with a number the answer is true.

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Mya told her friend, “If you increase my sisters age by 6, multiply that quantity by 12, and then subtract 4, you get 10. Write
Lostsunrise [7]

Answer: x+6(12-4) = 10

Step-by-step explanation:

7 0
3 years ago
Beverly drove from the Atlantic City to New York she drove 284 miles at a constant speed of 58 mph how long did it take Beverly
lubasha [3.4K]

Answer:

4.9 hours = 4 hours 54 minutes

Step-by-step explanation:

speed = distance/time

time * speed = distance

time = distance/speed

time = (284 miles)/(58 mph) = 4.9 hours

4.9 hours - 4 hours = 0.9 hours

0.9 hours * (60 minutes)/(1 hour) = 54 minutes

4.9 hours = 4 hours 54 minutes

8 0
3 years ago
Jillian is 5 years old. She has an older brother whose age is represented by the expression 2x+3, where x represents Jillian's a
abruzzese [7]

Answer:

13

Step-by-step explanation:

2(5) = 10, +3 = 13 years old,, just use order of operations and plug in jillians age for the x

4 0
3 years ago
Read 2 more answers
4 students from a class of 15 are going to be chosen to be on the dance committee. Find the number of different 4-person committ
Andrej [43]
We know that
The formula for combinations is
C=n!/[(n-r)!*r!]
where
n is the total number of objects you choose from
r is the number that you choose to arrange

in this problem
n=15 students
r=4 students
C=15!/[(15-4)!*4!]-----> C=15!/[11!*4!]---> (15*14*13*12*11!)/(11!*4*3*2*1)
C=(15*14*13*12)/(24)----->C=1365

the answer is
1365
7 0
3 years ago
Read 2 more answers
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
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