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2 years ago

Which is the value of this expression {jk^-2/j-1k-3}3, when j=-2 and k=-1?

Mathematics

1 answer:

Brut [27]2 years ago

4 0

Answer:

-9

Step-by-step explanation:

{-2*-1^-2/-2-1*-1-3}3

= -9

Answered by GAUTHMATH

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Please help! It's due soon.

Sedbober [7]

Answer:

Because f(g(x)) = g(f(x)) = x, f and g <u>are </u> inverse functions.

Step-by-step explanation:

f(g(x)) = f( $\frac{1}{4}\sqrt{x}$ ) = $16(\frac{1}{4}\sqrt{x} ) ^{2} = 16(\frac{1}{16}x)=x$

g(f(x)) = g $(16x^{2}) = \frac{1}{4}\sqrt{16x^{2} } = \frac{1}{4}(4x) = x$

6 0

3 years ago

salesperson receives 16.7% commission. If her total sales for the month are $4900, what is her commission?

Natali [406]

Answer:

$818,3

Step-by-step explanation:

16.7% in decimal is 0.167

= 0.167 x $4900

= $818,3

6 0

3 years ago

If you had carried out the algebra using variables before plugging numbers into your expressions, you would have found that (vf)

SashulF [63]

Answer:

Step-by-step explanation:

Volt is energy per electric charge

$1V=1J/C$

and the energy units in terms of meters, seconds and kilograms are:

$1J= 1kg\frac{m^{2}}{s^{2}}$

So the unit of volt is

$1V= kg \frac{m^{2}}{Cs^{2}}$

So the velocity expression (it can not be read completly) but i guess that it could be as follows

$vf_{a} = -2\sqrt{\frac{q_{a}\Delta V}{m_{a}}}$

So the unit analysis would be

$vf_{a} = \sqrt{\frac{C kg\frac{m^{2}}{Cs^{2}}}{kg}}}$

note that the coulomb unit of numerator is cancelled from the denominator. The same occurs for kg unit.

$vf_{a} = \sqrt{\frac{m^{2}}{s^{2}}}$

Applying square root

$vf_{a} = \frac{m}{s}$

7 0

3 years ago

You purchase a $220 Arline ticket. You have a discount code to receive 10% off. There is a 10.5% service charge added to the tot

antoniya [11.8K]

When you see % next to a number, you multiply it by .01.
10 becomes .1
10.5 becomes .105

220*.1=22, so this is the 10% off
220*.105=23.1, so this is the 10.5% service charge.

220-22+23.1=$221.10 for the ticket.

7 0

3 years ago

Assume that the weights of quarters are normally distributed with a mean of 5.67 g and a standard deviation 0.070 g. A vending m

Anuta_ua [19.1K]

Answer:

A) 1.96%

Step-by-step explanation:

You need to know the band between 5.48 g and 5.82 g, the mean is 5.67 g and the standard deviation is .0.070 g, with that information you can calculate the percentage to the left of the mean and the percentage to the right of the mean and add them.

To know its percentage you have to calculate the z score for both values.

$z = \frac{x-\mu}{\sigma}$

x is the value being evaluated

μ is the mean

σ is the standard deviation

For 5.48 g:

$z = \frac{5.48-5.67}{0.070} =-2.714$

and is equivalent to 0.0034

For 5.82 g:

$z = \frac{5.82-5.67}{0.070} = 2.143$

and is equivalent to 0.9838

Those numbers mean that the percentage below 5.48 is equivalent to the 0.34% of the values and the percentage below 5.82 is equivalent to 98.38% of the values. Then the percentage rejected is the percentage above 5.82, 100 - 98.38 = 1.62% plus the percentage below 5.48, 0.34%.

Percentage rejected = 1.62% + 0.34% = 1.96%

7 0

3 years ago