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Gekata [30.6K]
3 years ago
9

The area under the graph line

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

<u>The statement is true</u>: the area under the graph line made with the x-axis

represents the change in position of the object on a velocity versus time

graph.

Reasons:

\displaystyle Velocity  = \frac{Dislacement}{Time}

The area under the velocity time graph is given by the integration of the function for the velocity over the time interval.

A constant velocity is an horizontal line and the integration of a constant with time, gives the product of time and the constant, which is area under the rectangular graph.

Therefore, the area under the graph line made with the x-axis represents the change in position of the object on a velocity versus time graph.

Learn more here:

brainly.com/question/18910091

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C=3.95p what is the slope
N76 [4]

Step-by-step explanation:

I think it's 3.95!

this would be the only option!

6 0
3 years ago
Read 2 more answers
What are the coordinates of the center of the circle whose equation is x^2+y^2-16x+6y+53=0?
makkiz [27]
Hello :
<span>note : 
 an equation of the circle Center at the w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²  
in this exercice : </span><span>x²+y²-16x+6y+53=0
(</span>x²-16x) +( y²+6y ) +53 = 0
(x² -2(8)x +8² -  8²) +(y² +2(3)x -3²+3² ) +53=0
(x² -2(8)x +8²) -  8² +(y² +2(3)x +3²)-3²  +53=0
(x-8)² +( y+3)² = 20 

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8 0
3 years ago
Solve for the variable x.
inna [77]

Answer:

<u>x = 5</u>

Step-by-step explanation:

Equating the terms :

  • x + 3 = 2x - 2

Add 2 on both sides :

  • x + 3 + 2 = 2x - 2 + 2
  • x + 5 = 2x

Subtract x from both sides :

  • x + 5 - x = 2x - x
  • <u>x = 5</u>
3 0
2 years ago
Need help ASAP giving 15 points
aleksandr82 [10.1K]

Answer:

6,048

Step-by-step explanation:

l=3w

3w + 3w + w +w =96

8w =96

w=12

l= 36

12×36×14 = 6,048

7 0
3 years ago
Read 2 more answers
Dave drove to his friends house and back. It took one hour longer to go there than it did to come back. The average speed on the
mamaluj [8]

Remark

You know the most about the trip on the way back and the total of the two trips.

Way Back

r = 30 mph

d = distance traveled

t = t - 1 where t = the time to go there which we know nothing about

Total Distance

2d = 25 mph * (t + t - 1)

2d = 25 * (2t - 1)

2d = 50t  - 25                 Divide by 2

2d = 50t/2 - 25/2

d = 25t - 12.5

Equation coming back

d = 30*(t - 1)

d = 30t - 30

Comment

Since the distances are the same, equate them.

Solution

25t - 12.5 = 30t - 30                     Subtract 25t from both sides

25t - 25t -12.5 = 30t - 25t - 30   Combine like terms

-12.5 = 5t - 30                              Add 30 to both sides

-12.5 + 30 = 5t - 30 + 30             Combine

17.5 = 5t                                       Divide by 5

17.5/5 = t                                      Divide and Switch

t = 3.5

t is the time going there

t - 1 is the time coming back

Total time = 2*t - 1 = 2*3.5 - 1 = 6

The total time is 6 hours.   Answer


3 0
3 years ago
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