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Tanzania [10]
3 years ago
8

Sarah Meeham blends coffee for​ Tasti-Delight. She needs to prepare 190 pounds of blended coffee beans selling for ​$4.61 per po

und. She plans to do this by blending together a​ high-quality bean costing ​$6.50 per pound and a cheaper bean at ​$2.00 per pound. To the nearest​ pound, find how much​ high-quality coffee bean and how much cheaper coffee bean she should blend.
Mathematics
1 answer:
erastovalidia [21]3 years ago
6 0
I’m sorry I don’t know
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5+x/2 greater than or equal to 10
serious [3.7K]
5+x/2 < 10

10 is greater than 5+x/2

Please give brainliest :)
8 0
2 years ago
A six-sided die (with numbers 1 through 6) and an eight-sided die (with numbers 1 through 8) are rolled. What is the probability
Oduvanchick [21]

Answer:

1/4

Step-by-step explanation:

sorry for the messy work

6 0
3 years ago
The coordinates of an ordered pair have opposite signs. In which quadrant(s) must the ordered pair lie? Explain.
Alex_Xolod [135]
Alright...so the coordinates of an ordered pair have opposite signs [one sign is positive while the other is negative] so we could have an example of (-x,+y) or (+x,-y) ...that means out of the 4 quadrants these points could be in the 2nd quadrant or the 4th quadrant or corners of the graph

7 0
3 years ago
The area of a rectangle is 525 sq cm. the ratio of the length to the width is 7:3. find the length and width.
nalin [4]
Suppose the length is 7x, the width is then 3x
7x*3x=525
21x²=525
x²=25
x=5
so the length is 7*5=35, and the width is 3*5=15
3 0
3 years ago
At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards
katovenus [111]

Answer:

A

Step-by-step explanation:

The velocity of a moving body is given by the equation:

v=t^2-5t+4 ,\, t\geq0

Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.

And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

v

By substitution:

t^2-5t+4

Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:

(t-4)(t-1)=0

Zero Product Property:

t=1, \text{ and } t=4

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

v(0)=4>0,\, v(2)=-20

So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.

Hence, our answer is A.

7 0
3 years ago
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