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telo118 [61]
3 years ago
12

Hello i need help plz

Mathematics
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

the only one in five years ago and I have a good time to do so, I was just wondering 8th, I am a bit

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10(d+3)–(−9d–4)=d–5+3 <br><br> What value of d makes the equation TRUE?
rewona [7]
ANSWER

The value of d that makes the equation true is

d =  - 2



EXPLANATION

The given equation is

10(d + 3) - ( - 9d - 4) = d - 5 + 3


We expand brackets to obtain,

10d + 30 + 9d  + 4= d - 5 + 3


We group like terms to obtain,

10d +9d - d =  - 30 - 5 + 3 - 4


This simplifies to


18d =  - 36


We divide both sides by 18 to get,

d =  - 2
5 0
3 years ago
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The graph below shows the relationship between the number of chores that Larissa completes and the amount of money that she earn
Reil [10]

Answer:

2

Step-by-step explanation:

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PLEASE HELP ME I NEED THIS REALLY BAD
Galina-37 [17]

Answer:

z=70, y=102

Step-by-step explanation:

180-110 = 70

so, z=70

99+89+70 = 258

360-258 = 102

so, y=102

5 0
3 years ago
Find the volume of the rectangular prism.
Luden [163]

Answer:

30

Step-by-step explanation:

just becausr

6 0
3 years ago
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 55 o
Usimov [2.4K]

Answer:

a) For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

b) For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

c) We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

Step-by-step explanation:

For this case our random variable of interest for the weights is bell shaped and we know the following parameters.

\mu = 55, \sigma =6

We can see the illustration of the curve in the figure attached. We need to remember that from the empirical rule we have 68% of the values within one deviation from the mean, 95% of the data within 2 deviations and 99.7% of the values within 3 deviations from the mean.

Part a

For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

Part b

For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

Part c

We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

4 0
4 years ago
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