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3 years ago

Can someone help me understand how to do this

Mathematics

1 answer:

lukranit [14]3 years ago

3 0

When it comes to perimeter just add all the sides I’ll insert a picture

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What process do you use to find the percent change of a quantity?

Sever21 [200]

First, we need to get the amount of change:
The amount of change can either be an increase or a decrease.
It can be calculated as follows:
amount of change = $\frac{"new"value - "old"value}{"old" value}$

If the amount of change is positive, then it is an increase
If the amount of change is negative, then it is a decrease

Then, we need to convert this amount into a percentage:
Changing the amount into a percentage can simply be done by multiplying this amount by 100
This means that:
% of change = amount of change * 100

Combining the two steps:
% of change = $\frac{"new"value - "old"value}{"old" value}$ * 100

Examples:
The original price of a certain product was $10. It then became $12. Find the % of increase.
% of change = $\frac{12-10}{10} * 100$ = 20%
This means that the price increased by 20%

The temperature decreased from 25 degrees to 20 degrees. Find the percentage of decrease.
% of decrease = $\frac{20-25}{25} * 100$ = -20%
This means that the temperature decreased by 20%

Hope this helps :)

7 0

3 years ago

Read 2 more answers

• Yogi is planning a concert for his animal friends. He arranges his chairs and if he makes 8 rows he was

qaws [65]

Answer: Yogi has 59 chairs.

Step-by-step explanation: For the question, it's a lot of guess an check. 10 is a good place to start. Times 10 by 8 and add 3. Then times 6 by 10 and add 17. Does it equal the same number? No. Is it close? Yes. So maybe try going up a few numbers or down a few. You'll eventually get 7 which when you multiple 7 by 8 and add 3 and multiple 6 by 10 and add 17, you'll get 59.

5 0

3 years ago

Identify the mean, median, and mode for the dot plot below.01 2 3 4MathBits.comNumbers of Brothers and SistersMeanMedianMode =

telo118 [61]

The mean, median and mode is 2 of the given data from the dot plot.

Given, the table is :

Number of brothers and sisters 0,0,1,1,1,2,2,2,2,2,3,3,3,4,4

First the mean

Mean = average which = sum of data points / # of data points

Sum of data points = 0+0+1+1+1+2+2+2+2+2+3+3+3+4+4 = 30

# of data points ( count the number of dots ) = 15

So average (mean) = 30/15

= 2

Next lets find the median.

The median is the middle value.

We can find the median by listing the values and then meeting at the middle of the values

So we have 0,0,1,1,1,2,2,2,2,2,3,3,3,4,4

the list is odd, so we use median = n+1/2

= 15+1/2

= 16/2

= 8th term

= 2

Mode is simply the value that appears most.

The value that appears the most is 2 as it appears five times which is the most out of any other value.

Hence we get the mean, median and mode.

Learn more about Statistics here:

brainly.com/question/26941429

#SPJ9

6 0

1 year ago

Subject is Math pls help look at the photo :)

Stels [109]

1. 50
2. 154
3. 28
These would be your answers

5 0

3 years ago

Solve only if you know the solution and show work.

SashulF [63]

$\displaystyle\int\frac{\cos x+3\sin x+7}{\cos x+\sin x+1}\,\mathrm dx=\int\mathrm dx+2\int\frac{\sin x+3}{\cos x+\sin x+1}\,\mathrm dx$

For the remaining integral, let $t=\tan\dfrac x2$ . Then

$\sin x=\sin\left(2\times\dfrac x2\right)=2\sin\dfrac x2\cos\dfrac x2=\dfrac{2t}{1+t^2}$
$\cos x=\cos\left(2\times\dfrac x2\right)=\cos^2\dfrac x2-\sin^2\dfrac x2=\dfrac{1-t^2}{1+t^2}$

and

$\mathrm dt=\dfrac12\sec^2\dfrac x2\,\mathrm dx\implies \mathrm dx=2\cos^2\dfrac x2\,\mathrm dt=\dfrac2{1+t^2}\,\mathrm dt$

Now the integral is

$\displaystyle\int\mathrm dx+2\int\frac{\dfrac{2t}{1+t^2}+3}{\dfrac{1-t^2}{1+t^2}+\dfrac{2t}{1+t^2}+1}\times\frac2{1+t^2}\,\mathrm dt$

The first integral is trivial, so we'll focus on the latter one. You have

$\displaystyle2\int\frac{2t+3(1+t^2)}{(1-t^2+2t+1+t^2)(1+t^2)}\,\mathrm dt=2\int\frac{3t^2+2t+3}{(1+t)(1+t^2)}\,\mathrm dt$

Decompose the integrand into partial fractions:

$\dfrac{3t^2+2t+3}{(1+t)(1+t^2)}=\dfrac2{1+t}+\dfrac{1+t}{1+t^2}$

so you have

$\displaystyle2\int\frac{3t^2+2t+3}{(1+t)(1+t^2)}\,\mathrm dt=4\int\frac{\mathrm dt}{1+t}+2\int\frac{\mathrm dt}{1+t^2}+\int\frac{2t}{1+t^2}\,\mathrm dt$

which are all standard integrals. You end up with

$\displaystyle\int\mathrm dx+4\int\frac{\mathrm dt}{1+t}+2\int\frac{\mathrm dt}{1+t^2}+\int\frac{2t}{1+t^2}\,\mathrm dt$
$=x+4\ln|1+t|+2\arctan t+\ln(1+t^2)+C$
$=x+4\ln\left|1+\tan\dfrac x2\right|+2\arctan\left(\arctan\dfrac x2\right)+\ln\left(1+\tan^2\dfrac x2\right)+C$
$=2x+4\ln\left|1+\tan\dfrac x2\right|+\ln\left(\sec^2\dfrac x2\right)+C$

To try to get the terms to match up with the available answers, let's add and subtract $\ln\left|1+\tan\dfrac x2\right|$ to get

$2x+5\ln\left|1+\tan\dfrac x2\right|+\ln\left(\sec^2\dfrac x2\right)-\ln\left|1+\tan\dfrac x2\right|+C$
$2x+5\ln\left|1+\tan\dfrac x2\right|+\ln\left|\dfrac{\sec^2\dfrac x2}{1+\tan\dfrac x2}\right|+C$

which suggests A may be the answer. To make sure this is the case, show that

$\dfrac{\sec^2\dfrac x2}{1+\tan\dfrac x2}=\sin x+\cos x+1$

You have

$\dfrac{\sec^2\dfrac x2}{1+\tan\dfrac x2}=\dfrac1{\cos^2\dfrac x2+\sin\dfrac x2\cos\dfrac x2}$
$\dfrac{\sec^2\dfrac x2}{1+\tan\dfrac x2}=\dfrac1{\dfrac{1+\cos x}2+\dfrac{\sin x}2}$
$\dfrac{\sec^2\dfrac x2}{1+\tan\dfrac x2}=\dfrac2{\cos x+\sin x+1}$

So in the corresponding term of the antiderivative, you get

$\ln\left|\dfrac{\sec^2\dfrac x2}{1+\tan\dfrac x2}\right|=\ln\left|\dfrac2{\cos x+\sin x+1}\right|$
$=\ln2-\ln|\cos x+\sin x+1|$

The $\ln2$ term gets absorbed into the general constant, and so the antiderivative is indeed given by A,

$\displaystyle\int\frac{\cos x+3\sin x+7}{\cos x+\sin x+1}\,\mathrm dx=2x+5\ln\left|1+\tan\dfrac x2\right|-\ln|\cos x+\sin x+1|+C$

5 0

3 years ago