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3 years ago

Can someone please help me g(x) = 17 -*; g(6)

Mathematics

2 answers:

Sav [38]3 years ago

6 0

Answer:

Divide each term in G(6)=17−(2/3)x by 6.

G(6)/6=17/6−(2/3)x⋅16

Cancel the common factor of 6.

G=17/6−(2/3)x⋅16

Simplify each term.

G=17/6−x/9

Step-by-step explanation:

DerKrebs [107]3 years ago

3 0

Answer:

(x + 6)(x-4) = -16

x² + 2x -24 = -16

x² + 2x - 8 = 0

(x + 4)(x-2) = 0

x = - 4 or x = 2

Step-by-step explanation:

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Maria needs to buy cat food. At Save Rite, cat food costs $5.25 for 3 cans. Spend Less offers cat food at $7.50 for 5 cans. Mari

ozzi

Answer:

Step-by-step explanation:

First, in order to find the lowest price, you have to find the cost for 1 can in each store.

Save Rite: Since it is $ 5.25 for 3 cans, you divide 5.25 by 3. The quotient is 1.75. So, the price is $ 1.75 per can.

Then you do the same for Spend Less.

Spend Less: Since it is $ 7.50 for 5 cans, you divide 7.5 by 5. The quotient is 1.5. So, the price is $ 1.50 per can.

Since Save Rite's price for one can is $ 0.25 more than Spend Less, it is more expensive.

So in order to see how much she paid for 15 cans from the cheapest store, you would have to multiply 15 by 1.5.

The answer is 22.50.

The answer is C

7 0

3 years ago

Read 2 more answers

1. Trapezoid KLMN has vertices K(1, 3) , L(3, 1) , M(3, 0) , and N(1, −2) .

chubhunter [2.5K]

Answer:

Step-by-step explanation:

(A) The vertices of the trapezoid KLMN are K(1, 3) , L(3, 1) , M(3, 0) , and N(1, −2)

Now, KL= $\sqrt{(3-1)^{2}+(1-3)^{2}}$ =\sqrt{8}[/tex]

LM= $\sqrt{(3-3)^{2}+(0-1)^{2}}=1$

MN= $\sqrt{(1-3)^{2}+(-2-0)^{2}}=\sqrt{8}$

NK= $\sqrt{(1-1)^{2}+(-2-3)^{2}}=5$

Now, as KL and MN are equal, therefore, KLMN is an isosceles trapezoid.

(B) Since m∠XWY=47°, therefore ∠XWZ=47+47=94° and ∠ZYW=18°, therefore ∠XYZ=36°( as diagonals bisect the angles)

In ΔXWO,

∠XWO+∠WXO+∠WOX=180°(Angle sum property)

∠WXO=43°

Also, from ΔXOY,

∠OXY=72° using the angle sum property.

Therefore, ∠WXY=43+72=115°

Now, sum of all the angles of a quadrilateral is equal to 360°, therefore

∠WXY+∠XYZ+∠YZW+∠ZWX=360°

115°+36°+∠YZW+94°=360°

∠YZW=115°

Therefore,∠WZY=115°

LetM be the mid point of AB, therefore M= $(\frac{-2+4}{2}, \frac{4+3}{2})$

= $(1,\frac{7}{2})$

Also, let N be the mid point of DC, therefore,

N= $(\frac{4-2}{2},\frac{-2-5}{2})$

= $(1,\frac{-7}{2})$

Now, length of the mid segment MN= $\sqrt{(1-1)^{2}+(\frac{7}{2}+\frac{7}{2})^{2}}=\sqrt{0+49}=7 cm$

(D)Given: Kite PQRS, TS=6cm and TP=8cm

Then, From triangle TSP, we have

$(SP)^{2}=(TS)^{2}+(TP)^{2}$

$(SP)^{2}=36+64$

$SP=10cm$

8 0

3 years ago

A triangle has two sides of lengths 7 and 12. What value could the length of the third side be? Check all that apply.

yaroslaw [1]

Third side must be greater than (12 -7) or 5 and less than (12 + 7) or 19
So, third side could be A C E or F

5 0

3 years ago

Read 2 more answers

What is the value of 7(3× -4)+4³,when ×=6

jolli1 [7]

The answer is -20 I hope this helped

6 0

3 years ago

The question is attached

DerKrebs [107]

$cos(A - B) = cos A cos B + sin A sin B$

In this case, A is $\frac{\pi }{3}$ and B is $\frac{\pi }{5}$ , so:

$cos\frac{\pi}{3} cos\frac{\pi}{5} +sin\frac{\pi }{3} sin\frac{\pi }{5} =cos(\frac{\pi}{3} -\frac{\pi}{5} ) = cos\frac{2\pi}{15}$

Hope that helps!

5 0

2 years ago