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monitta
3 years ago
10

Can someone please help me g(x) = 17 -*; g(6)

Mathematics
2 answers:
Sav [38]3 years ago
6 0

Answer:

Divide each term in G(6)=17−(2/3)x by 6.

G(6)/6=17/6−(2/3)x⋅16

Cancel the common factor of 6.

G=17/6−(2/3)x⋅16

Simplify each term.

G=17/6−x/9

Step-by-step explanation:

DerKrebs [107]3 years ago
3 0

Answer:

(x + 6)(x-4) = -16

x² + 2x -24 = -16

x² + 2x - 8 = 0

(x + 4)(x-2) = 0

x = - 4 or x = 2

Step-by-step explanation:

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5 0
2 years ago
Help PLEASESSS due in 20
kicyunya [14]
  1. 4 - 4 + 4 ÷ 4
  2. 4 ÷ 4 + 4 ÷ 4
  3. (4 + 4 + 4) ÷ 4
  4. √4 + √4 + 4 - 4
  5. √4 + 4 + 4 ÷ 4
  6. √4 + 4 + 4 - 4
  7. 4 + 4 - 4 ÷ 4
  8. 4 + 4 + 4 - 4
  9. 4 + 4 + 4 ÷ 4
  10. √4 + √4 + √4 + 4
  11. 44/(√4 + √4)
  12. √4 + √4 + 4 + 4
  13. 44/4 + 4
  14. 4 + 4 + 4 + √4
  15. 44/4 + 4
  16. 4 * 4 * 4 ÷ 4
  17. 4 * 4 + 4 ÷ 4
  18. 4 * 4 - √4 + 4
  19. 4! - 4 - 4 ÷ 4
  20. 4 * (4 + 4 ÷ 4)
  21. 4! - 4 + 4 ÷ 4
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Lol, that took a while, hope it helps!

7 0
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