The length of AB would be 38 units
<h3>How to determine the length AB?</h3>
The attached image represents the missing piece in the question
Considering the triangle BCD;
Calculate the length BC using the following Pythagoras theorem
BC^2 = CD^2 + BD^2
This gives
BC^2 = 10^2 + 8^2
Evaluate
BC^2 = 164
Considering the triangle CBA;
Calculate the length AB using the following Pythagoras theorem
AB^2 = AC^2 - BC^2
This gives
AB^2 = 40^2 - 164
Evaluate
AB^2 = 1436
Take the square root
AB = 38 (approximated)
Hence, the length of AB would be 38 units
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Answer:
what i didnt understood this question from which country u r
Carson needed pencil and erasers, but the total amount can not be over 40. Pencils were $4 and erasers were 5$. How much pencils and erasers can he buy without spender over $80
The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
<h3>What is the area of the rectangle?</h3>
It is defined as the area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
We have:
The length of a new rectangle playing field is 6 yards longer than quadruple the width.
Let's suppose the length is l and width is w of a rectangle:
From the problem:
l = 6 + 4w
Perimeter P = 2(l + w)
532 = 2(l + w)
Plug l = 6+4w in the above equation:
532 = 2(6 + 4w + w)
266 = 6 + 5w
260 = 5w
w = 52 yards
l = 6 +4(52) = 214 yards
Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.
Learn more about the area of rectangle here:
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