4(h+11)-15 The solution
1 answer:
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Answer:
49.7%
Step-by-step explanation:
A cdircle is located within a square.
<u>Area of the circle</u>
Area = , where r = 4 units.
Area Circle = 50.3 units^2
<u>Area of the square</u>
Area = l*w or l^2 for a square, since l = w
Area = (10 units)^2
Area = 100 units^2
<u>Area in the square but outside the circle</u>
This is the difference [Square minus Circle Areas]
Square minus Circle Areas = 100 - 50.3 or <u>49.7 units^2</u>
<u>Probability</u>
The probability of picking a point in the square that is not in the circle is the ration of the two areas: <u>[Outside Circle/Square]x100%</u>
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<u>(</u>49.7 units^2)/(100 units^2)x100% = 49.7%
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