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galina1969 [7]
3 years ago
7

Which equation represents a line which is parallel to x = 0? helppp pleaseee

Mathematics
2 answers:
faltersainse [42]3 years ago
8 0

Answer:

The right answer is y=-7

Hope this helps :3

Step-by-step explanation:

alexgriva [62]3 years ago
7 0

Answer:

Y = x

Step-by-step explanation:

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Brian deposits $7000 into an account that pays simple interest at an annual rate of 3%. He does not make any more deposits. He m
Andre45 [30]

Answer:

A)1050

B)8050

Step-by-step explanation:

to find interest we use the formula A= P(1+rt) where P is the initial investment, r is the rate percent, and t is the time interval

for this question we have A=7000(1+3(5)) which gives 8,050 dollars which is the answer to part B

for part A we simply subtract the answer from B from the initial investment so 8050 - 7000 = 1050 made from interest

4 0
2 years ago
Decompose 3/8 as the sum of unit fractions
bearhunter [10]
Unit fractions are fractions with a 1 as the numerator(number on top)
so 3/8 equals 1/8+1/8+1/8
8 0
3 years ago
Write a statement that indicates that the triangles in each pair are congruent
lyudmila [28]

Answer:

ans:

  1. option B
  2. option A
  3. option B
  4. option A

Step-by-step explanation:

for two triangle to be congruent corresponding sides and angle must be equal

8 0
3 years ago
annie puts 10 dollars into a vacation jar each week.how much will she have saved by the ebd of the week
lubasha [3.4K]
Annie will have $70 because if you multiply 7 times 10 you get 70
5 0
3 years ago
Read 2 more answers
given : AD is ⊥to AB and DC, BC is ⊥ to AB and DC, angle EDC ≅ angle ECD, AD ≅ BC. prove: triangle ADE ≅ triangle BCE
Kamila [148]

Answer:

Hence proved triangle ADE ≅ triangle BCE by Side Angle Side congruent property.

Step-by-step explanation:

Given:

AD ⊥ AB \& CD

BC ⊥ AB \& CD

AD = BC

∴ ∠ A = ∠ B = ∠ C = ∠ D =90°

∠ EDC = ∠ ECD

Solution

∠ C = ∠ BCE + ∠ ECD⇒ equation 1

∠ D = ∠ ADE + ∠ EDC⇒ equation 2

∠ C = ∠ D (given)

Substituting equation 1 and 2 in above equation we get

∠ BCE + ∠ ECD = ∠ ADE + ∠ EDC

But ∠ EDC = ∠ ECD (given)

∴ ∠ ADE = ∠ BCE

ED = EC (∵ base angles are same triangle is isosceles triangle)

Now, In Δ ADE and Δ BCE

AD =BC

∠ ADE = ∠ BDE

ED = EC

∴ By Side Angle Side congruent property

Δ ADE ≅ Δ BCE

6 0
3 years ago
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