Answer:
9.17 feet.
Step-by-step explanation:
See the diagram attached to this answer.
Let, AB is the pole and CD is the tree.
From the top of the pole to the base of the tree the angle of depression as per the condition is 63°.
So, ∠ EBC = ∠ ACB = 63° {Since, BE ║ AC}
So, from Δ ABC,
{Given height of the tower AB = 18 feet}
⇒
feet.
Therefore, the distance between the pole and the tree is 9.17 feet. (Answer)
Answer:
a) a^6+6a^4b+15a^2b^2+20b^3+15(b^4/a^2)+6(b^5/a^4)+(b/a)^6
b) 20
c) a^6+6a^4+15a^2+20+15/a^2+6/a^4+1/a^6
Step-by-step explanation:
(a+b/a)^6=a^6+6a^5(b/a)+15a^4(b/a)^2+20a^3(b/a)^3+15a^2(b/a)^4+6a(b/a)^5+(b/a)^6
a^6+6a^4b+15a^2b^2+20b^3+15(b^4/a^2)+6(b^5/a^4)+(b/a)^6
b) the coefficient of b^3=20
c) if b=1, the expression is
a^6+6a^4+15a^2+20+15/a^2+6/a^4+1/a^6
Answer:
x = 26 - 14
14 = 26 - x
Step-by-step explanation:
Answer:
New bed dimension of bed 0.5 ft, 0.25 ft
New bed dimension of room 1.16 ft, 1.33 ft
Step-by-step explanation:
Given data:
bed dimension is given as 6 ft by 3 ft
room dimension is given as 14 ft 16 ft
according to the given information , new dimension of the room and bed will be 1/12 times of actual dimension. therefore we have
New bed dimension of bed 
= 0.5 ft, 0.25 ft
New bed dimension of room 
= 1.16 ft, 1.33 ft