The equation of the line is y = -2x + 16 which passes through the point (4, 8) and has a slope of -2.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
It is given that:
The line that passes through the point (4, 8) and has a slope of -2.
On comparing the standard equation:
y = mx + c
Here m is the slope of the line and c is the y-intercept.
m = -2
y = -2x + c
Plug x = 4 and y = 8
8 = -2(4) + c
c = 16
y = -2x + 16
Thus, the equation of the line is y = -2x + 16 which passes through the point (4, 8) and has a slope of -2.
Learn more about the linear equation here:
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Velocity is speed. It doesn't matter what direction.
First you grapgh 0,-3 then you follow the slope of going 4 up 5 to the right and contine up also on e-where it is 0,-3 you go down 4 and 5 to the left and contine that to make a straught line.
Given :
Now, Substituing the value of y in equation (ii) :
Now, substituting the value of x in equation (i) :
Answer:log₂(
)
Explanation:Before we begin, remember the following:logₐ(x) - logₐ(y) = logₐ(
)
alog(x) = log(xᵃ)
Now, for the given we have:3 log₂(x) - (log₂3 - log₂(x+4))
log₂(x²) - log₂(
)
log₂(
) = log₂(
)
Hope this helps :)
