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3 years ago

Y=6x+21 -x+3y=12 Find x and y please

Mathematics

1 answer:

rosijanka [135]3 years ago

3 0

For first one
Y=6x+21 can’t be changed
X=y/6-7/2
for the second
X=-12+3y
Y=4+x/3

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The school that Darryl goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold 9 ad

hram777 [196]

Answer:

look at picture

Step-by-step explanation:

x: adult tickets

y: student tickets

8 0

3 years ago

The volumes of a water balloon and an air balloon after they are punctured are represented by the

spin [16.1K]

Answer:

Both air balloon and water balloon data are best modeled by an exponential function.

Step-by-step explanation:

Air balloon

Time (seconds) Volume (cubic centimeters)

0 95

3 69

6 50

9 37

12 27

The relation Volume variation/time is constant for lines, In this case, this value change from point to point, as can be seen next.

(69 - 95)/3 = -8.67

(50 - 69)/3 = -6.33

(37 - 50)/3 = -4.33

(27 - 37)/3 = -3.33

Water balloon

Time (seconds) Volume (cubic centimeters)

0 30

3 15.8

6 7.8

9 4

12 2

(30 - 15.8)/-3 = -4.73

(15.8 - 7.8)/-3 = -2.67

(7.8 - 4)/-3 = -1.27

(4 - 2)/-3 = -0.67

In this case, the relation Volume variation/time also change from point to point.

Then, both air balloon and water balloon data are best modeled by an exponential function.

6 0

3 years ago

Write the equation in slope-intercept form (y=mx + b) for a line with a slope of 2/3 and a y-intercept of -5.

adelina 88 [10]

Y=mx+b
b= y-intercept
-5=2/3x+b
answer: y=2/3x-5

5 0

3 years ago

Jane has three boxes she needs to ship. Box X weighs 33 kg more than Box Y and Box Z weighs 12 kg more than Box Y. She

andreyandreev [35.5K]

Answer:

$3w+45=557$

Step-by-step explanation:

Let the weight of box Y be w kg.

Box X weighs 33 kg more than Box Y, then the weight of box X is

$w+33$ kg.

Box Z weighs 12 kg more than Box Y, then the weight of box Z is

$w+12$ kg.

The total weight of all boxes is

$w+(w+33)+(w+12)=w+w+33+w+12=3w+45$ kg

Jane measured the total weight of all the boxes and it was found to be 557 kg, therefore,

$3w+45=557$

$3w=512$

3 0

3 years ago

DOES ANYONE KNOW THE ANSWERS TO THESE PROBLEM, PLZ HELP!

Virty [35]

Answer:

Q.1.

Sum of angles of a triangle = 180°

∠A + ∠B + ∠c = 180

(3x - 9) + (4x + 15) + 90 = 180

3x - 9 + 4x + 15 + 90 = 180

7x + 96 = 180

7x = 84

x = 12

∠A = 3x - 9 = 3(12) - 9 = 36 - 9 = 27°

∠B = 4x + 15 = 4(12) + 15 = 48 + 15 = 63°

∠A = 27°

∠B = 63°

Q.2.

$using \ pythagoras \ theorem \\x^2 = 7^2 + (7\sqrt{3} )^{2} = 49 + 49(3) = 196\\x = \sqrt{196} = 14$

$sin y = \frac{opposite}{hypotenuse} = \frac{7\sqrt{3} }{14} = \frac{\sqrt{3} }{2} \\\\y = sin^{-1} (\frac{\sqrt{3} }{2} ) = 60$

x = 14

y = 60°

8 0

3 years ago