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3 years ago

Is 2/3(x-4)=1/3(2x-6) a identity

1 answer:

8 0

It is a property. Distributive property but they only multiplied in 2 instead of the whole fraction of (2/3). That is why the (x-4) changed to (2x-6) and the fraction is no longer 2/3 but 1/3.

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A triangle in the xy-coordinate plane is formed by the points (3, 5), (− 1, 5) , and (3,− 6) . What is the perimeter and area of

kati45 [8]

Answer:

Therefore, the perimeter of the triangle is 26.7 units and the area is 22 square units.

Step-by-step explanation:

Given the vertices of a triangle as: A(3, 5), B(− 1, 5), and C(3,− 6)

Since A and B are on the same y-coordinate, we have that:

AB = 3-(-1)=4 Units

Since A and C are on the same x-coordinate, we have that:

AC=5-(-6)=11 Units

Next, we determine the distance BC using the distance formula.

Given: B(− 1, 5), and C(3,− 6)

$BC=\sqrt{(3-(-1))^2+(-6-5)^2}\\= \sqrt{(4)^2+(-11)^2}=\sqrt{137}$ Units$

Therefore:

Perimeter of the Triangle

$= 4+11+\sqrt{137}\\ =15+\sqrt{137}$ Units\\=26.7 Units$

On plotting the triangle, it forms a right triangle such that the:

Base = 4 Units

Height = 11 Units

Therefore:

Area of a triangle $=\dfrac12 *Base*Height$

Therefore:

Area of the Triangle = 0.5 X 4 X 11

=22 Square Units.

Therefore, the perimeter of the triangle is 26.7 units and the area is 22 square units.

5 0

3 years ago

What is half of 3.8 million

Aleks [24]

One million nine hundred thousand

3 0

3 years ago

Read 2 more answers

A peculiar die has the following properties: on any roll the probability of rolling either a 2, a 3, or a 5 is 1/2, just as it i

igor_vitrenko [27]

Answer:

A. P( 2∪3∪1 )=1/2

B. P( 2∪3∪4∪5∪6 )= 13/16

Step-by-step explanation:

A. At first we need to get all the information that we can from the question, so we focus on the probabilities given P(2∪3∪5)=1/2 and P(4∪5∪6)=1/2 and we need to use P(5)=3/16.

Notice that when you have a dice, it´s impossible to get two values at the same try. Because of this and the property of probability for events:

P(2∪3∪5)=P(2) + P(3) + P(5) - P(2∩3)(=0) - P(3∩5)(=0) - P(2∩5)(=0) + P(2∩3∩5)(=0)

P(2∪3∪5)=P(2) + P(3) + P(5)

1/2=P(2) + P(3) + 3/16

P(2)+P(3)=5/16

If we do the same with P(4∪5∪6), we get:

P(4)+P(6)=5/16

Now, with this new information we can find P(1):

P(1)= 1 - P(2∪3∪4∪5∪6)

P(1)= 1 - (P(2) + P(3) + P(4) + P(5) + P(6)) (The probability of two of them happening at the same time is zero)

P(1)= 1 - (5/16 + 5/16 + 3/16)

P(1)= 1 - 13/16

P(1)= 3/16

And with it, we can find P(2∪3∪1):

P(2∪3∪1)=P(2)+P(3)+P(1)

P(2∪3∪1)=5/16+3/16

P(2∪3∪1)=1/2

B. Notice if you want to roll anything but a 1, then the probability you are looking for is "P(2∪3∪4∪5∪6)" but we found that in part A

P(2∪3∪4∪5∪6)=13/16

4 0

3 years ago

List all the factor pairs in the table factors of 25

Amiraneli [1.4K]

1,5,25 are the factors

4 0

3 years ago

Read 2 more answers

24y-32 pls help ill give you 10 points

belka [17]

Answer:

8(3y-4)

hope this help :)

8 0

2 years ago