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jarptica [38.1K]
3 years ago
6

Ryan and Scott are each studying a square pyramid.

Mathematics
2 answers:
Charra [1.4K]3 years ago
7 0

Answer: D

Step-by-step explanation: It's not C

Rufina [12.5K]3 years ago
3 0

Answer:

I think C is the answer for this equation.

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If 0.000023 is expressed in the form 2.3*10n what is the value of n
Inga [223]
N = 5
Because you have to the decimal 5 places to the right.
0.000023 = 2.3×10^5
3 0
4 years ago
A function ,f, is defined by the set {(2,3), (4,7), (-1,5)}. if f is reflected in the line y=x, which point will be in the refle
kotykmax [81]

Answer:

the answer is d

Step-by-step explanation:

6 0
3 years ago
Question:
Flauer [41]

17 spaces. Just jump from each space to the next until you get to (-5,-4). :) hope it helps.

8 0
3 years ago
Nine tiles are numbered $\color[rgb]{0.35,0.35,0.35}1, 2, 3, \ldots, 9$. Each of three players randomly selects and keeps three
Eduardwww [97]

The probability that all three players obtain an odd sum is 3/14.

<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.

The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in ^3C_1  ways.

The 3 odd tiles out of 5 can be selected in ^5C_3 ways.

The remaining 2 odd tiles can be selected and distributed in ^2C_1 ways.

The remaining 4 even tiles can be equally distributed in \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !} ways.

So, the possible distributions = ^3C_1 × ^5C_3 × ^2C_1 × \frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}

⇒ 3 × 10 × 2 × 6 = 360

To find the total distributions,

The first player needs 3 tiles from the 9 tiles in ^9C3=84 ways

The second player needs 3 tiles from the remaining 6 tiles in ^6C_3=20 ways

The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

#SPJ4

3 0
2 years ago
What is the perimeter of the truss in feet?
Zanzabum

I think the truss is just one of those triangles whose sides are 3ft, 3ft, 3ft so its perimeter is


Answer: 9 feet



5 0
4 years ago
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