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2 years ago

Congruent figures have the _ size and the _ shape.

Mathematics

2 answers:

oksian1 [2.3K]2 years ago

7 0

Congruent figures have the same size and the same shape

kotegsom [21]2 years ago

4 0

Same and same. They're congruent which means they have the same size and the same shape.

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A small country consist of four states the population of state Inc. is 67,200 the population of CB is 78,300 the population of s

hammer [34]

Answer:

Step-by-step explanation:

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3 years ago

Which is a factor of 21?<br> 4<br> 3<br> 6<br> 5

arsen [322]

Answer:

Step-by-step explanation:

Using listing:

$1 \times 21 = 21$

$3 \times 7 = 21$

No other factors are possible.

Hence, 1, 3, 7 and 21 are factors of 21.

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2 years ago

Read 2 more answers

What are the exact solutions of x2 − 5x − 1 = 0 using x equals negative b plus or minus the square root of the quantity b square

geniusboy [140]

Answer:

$x=2.5+\frac{\sqrt{29}}{2}\\\\x=2.5-\frac{\sqrt{29}}{2}$

Step-by-step explanation:

So the question here is asking you to use the quadratic formula which is expressed as: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\$

A quadratic can generally be expressed as: $y=ax^2+bx+c$

So using the equation you gave: $0=x^2-5x-1$

We can identify the following values: a=1, b=-5, c=-1

Btw the equation explicitly write "1" as the coefficient of x, but since it's not provided it's implied that it's 1.

So plugging in the known values, we get the following equation:

$x=\frac{5\pm\sqrt{(-5)^2-4(1)(-1)}}{2(1)}\\\\x=\frac{5\pm\sqrt{25+4}}{2}\\\\x=\frac{5\pm\sqrt{29}}{2}\\\\x=2.5+\frac{\sqrt{29}}{2}\\\\x=2.5-\frac{\sqrt{29}}{2}$

The last step just consists of taking the + and - solution, and since it asks for exact solutions you leave the 29 under the radical, and you don't approximate. There is no further simplification that can be done here.

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1 year ago

Jessica and Josh are selling Entertainment Books to raise money for the art room at their school. One book sells for $15. Jessic

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Answer: Josh sold 11 book shows and Jessica sold 198 books.

Look at the attachment for the work.