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Alex17521 [72]
3 years ago
14

Please help me with these questions.

Mathematics
1 answer:
guajiro [1.7K]3 years ago
7 0
There's no questions?
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How many solutions does this equation have? 3y = –4 + 2y
Akimi4 [234]

Answer:

4

Step-by-step explanation:

3y - 4 + 2y

0 = 3y - 4 + 2y

4 + 0 = 3y - 2y

4 = y

y = 4

is this what you want ?

4 0
3 years ago
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Simplify: - 2/5+4/3​
icang [17]

Answer:

14/15

Step-by-step explanation:

5 0
3 years ago
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If a system of linear equations has no solution, what do you know about the slopes and y-intercepts of the graphs of the equatio
Nata [24]

Answer:

B. The slopes of the graphs are the same and the y-intercepts of the graphs are different

Step-by-step explanation:

The lines will also be parallel

7 0
3 years ago
Captain's Autos sells 22 used cars on
aliina [53]

Answer:

160

Step-by-step explanation:

22 + 18 = 25 percent

40 = 25 percent

100 / 25 = 4

40 x 4 = 160.

3 0
1 year ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

3 0
3 years ago
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