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Vsevolod [243]
2 years ago
10

Find the equation of the line, in point-slope form then slope-intercept form, that

Mathematics
1 answer:
AleksandrR [38]2 years ago
8 0

Answer:

Point slope: y+4=4(x-3)

Slope-intercept: y=4x-16

Step-by-step explanation:

1. Use the slope formula to find the slope.

y2-y1/x2-x1

8--4/6-3 = 12/3

Slope is 4

2. Use the slope and one of the coordinates to put the equation in point-slope form.

Point slope form: y-y1=m(x-x1)

y+4=4(x-3)

3. Distribute and simplify to put it in slope-intercept form.

y+4=4x-12

y=4x-16

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Donald spends a total of $17.43 on peanuts that cost $2.49 per pound. How many pounds of peanuts does he buy?
True [87]

Answer:

He bought 7 pounds of peanuts

Step-by-step explanation:

17.43/2.49=7

4 0
2 years ago
What is the standard form for the quadratic function?<br> g(x) = (x + 1)^2– 2
zloy xaker [14]

Answer: g(x)=x^2+x-1

Step-by-step explanation:

(x+1)^2-2

x^2+2*1*x+1^2-2\\x^2+2x+1-2\\x^2+x-1

3 0
2 years ago
2. A statistics student plans to use a TI-84 Plus calculator on her final exam. From past experience, she estimates that there i
Anarel [89]

Answer:

  1. P(≥1 working) = 0.9936
  2. She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.

Step-by-step explanation:

1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...

... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936

2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.

If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.

This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.

_____

My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)

7 0
3 years ago
Help and please explain (20 points, will reward brainliest :))
notka56 [123]

Answer:x=13

BMC=75 degrees

Step-by-step explanation:

(x+2)+(5x+10)=90 degrees

so 6x+12=90

x=13

5x+10=5x13+10=75 degrees

7 0
3 years ago
Help please I need 5 points total. i need 2 to left of vertex. i need vertex. i need 2 to right of vertex. Please, quickly, I am
zlopas [31]

We are given with a quadratic equation which represents a Parabola , we need to find the vertex of the parabola , But let's recall that , For any quadratic equation of the form ax² + bx + c = 0 , the vertex of the parabola is given by ;

{\quad \qquad \boxed{\bf{Vertex = \left(\dfrac{-b}{2a},\dfrac{-D}{4a}\right)}}}

Where , D = b² - 4ac (Discriminant)

Now , On comparing the given equation with ax² + bx + c , we have

⇢⇢⇢ <em><u>a = 1 , b = - 10 , c = 2</u></em><em><u>7</u></em>

Now , Calculating D ;

{:\implies \quad \sf D=(-10)^{2}-4\times 1\times 27}

{:\implies \quad \sf D=100-108}

{:\implies \quad \bf \therefore \quad D=-8}

Now , Calculating the vertex ;

{:\implies \quad \sf Vertex =\bigg\{\dfrac{-(-10)}{2\times 1},\dfrac{-(-8)}{4\times 1}\bigg\}}

{:\implies \quad \sf Vertex = \left(\dfrac{10}{2},\dfrac{8}{2}\right)}

{:\implies \quad \bf \therefore \quad Vertex = (5,2)}

Hence , The vertex of the parabola is at (5,2)

Note :- As the Discriminant < 0 . So , the equation will have imaginary roots .

Refer to the attachment for the graph as well .

5 0
2 years ago
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