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Viktor [21]
3 years ago
10

Which algebraic expression is equivalent to the expression below?

Mathematics
2 answers:
vredina [299]3 years ago
5 0

Answer:

b is trueeeeeeee answer

16x+24+3x = 19x+24

nataly862011 [7]3 years ago
4 0

Step-by-step explanation:

4(4x+6)+3x

16x+24+3x

16x+3x+24

19x+24

19x+6

A. 19x+6

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Minchanka [31]
Is there supposed to be a picture attached?
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3 years ago
Model Exponential Growth Question :A sample of bacteria is growing at a continuously compounding rate. The sample triples in 10
Iteru [2.4K]

Answer:

The number of bacteria B after d days is given by

B = B_0 (3)^{\frac{1}{10} d}

where B_0 is the initial number of bacteria.  

Step-by-step explanation:

The number of bacteria B in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

B = B_0 *3,

where B_0 is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

B = (B_0 *3)*3

after the 3rd day,

B =( B_0 *3*3)*3

and so on.

Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

B = B_0 (3)^n

where n is is the <em>n</em>th 10-days.

Since, n is 10 days, we have

d =10n

or

n =\dfrac{1}{10}

Substituting that into B = B_0 (3)^n, we get:

\boxed{ B = B_0 (3)^{\frac{1}{10} d}}

8 0
3 years ago
The national weather service keeps records of rainfall in valleys. Records indicate that in a certain valley the annual rainfall
Setler79 [48]

Answer:

The mean is 95 and the standard deviation is 2

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Population:

Mean 95, Standard deviation 12

Samples of size 36:

By the Central Limit Theorem,

Mean 95

Standard deviation s = \frac{12}{\sqrt{36}} = 2

4 0
3 years ago
Adrian's computer cost 20% less than Jocelyn's computer. Adrian's computer cost $640. Adrian's computer cost 15% more than Corbi
OLEGan [10]

Answer:

640 = .8j

640 = 1.15c

Step-by-step explanation:

Let j = cost of Jocelyn's computer

c = cost of Corbin's computer

We know that Adrian's computer costs $640.

Since Adrian's computer costs 20% less than Jocelyn's computer, the cost of Adrian's computer is 80% of (.8 times)the cost of Jocelyn's computer, so 640 = .8j

Since Adrian's computer costs 15% more than Corbin's computer, the cost of Adrian's computer is 115% of (1.15 times) the cost of Corbin's computer, so 640 = 1.15c

7 0
2 years ago
Solve for x. 9≤17−4x9≤17−4x
Readme [11.4K]

not sure that that can be solved


8 0
3 years ago
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