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Tom [10]
2 years ago
9

Can you help me on unmber 2 or 3 Plzz show work

Mathematics
1 answer:
NikAS [45]2 years ago
3 0

Step-by-step explanation:

In,

Question 2 I have already answered,

Q. 3)

<h3><em><u>Given</u></em><em><u> </u></em><em><u>Question</u></em><em><u>:</u></em></h3>

\frac{ {c}^{2} }{d}

<em><u>Given</u></em><em><u> </u></em><em><u>values</u></em><em><u>:</u></em><em><u>-</u></em>

c = 6 , d = 3

<em><u>By</u></em><em><u> </u></em><em><u>putting</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>values</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>question</u></em><em><u>, </u></em>

\frac{ {6}^{2} }{3}

=  \frac{36}{3}

= <em><u>12 (Ans)</u></em>

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Find the inverse: f(x)=x+5/3x-1<br><br> f^-1x=
babunello [35]

We have f(x)=\dfrac{x+5}{3x-1}.

To find inverse function f^{-1}(x) we substitute x with f^{-1}(x) and vice-versa to get

x=\dfrac{f^{-1}(x)+5}{3f^{-1}(x)-1}

Now solve for f^{-1}(x). Note that I will use j instead.

x=\dfrac{j+5}{3j-1} \\x(3j-1)=j+5 \\3jx-x=j+5 \\3jx-x-j-5=0 \\3jx-j=x+5 \\j(3x-1)=x+5 \\j=\dfrac{x+5}{3x-1}

So we find that f(x)=f^{-1}.

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Answer: -1

Step-by-step explanation:

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photoshop1234 [79]

Answer:

\huge{ \boxed{ \sf{19}}}

Step-by-step explanation:

\underline{ \sf{Given}} :  \sf{y = 12}

\underline{ \sf{To \: Find}} :   \sf{Value \: of \: the \: given \: expression}

\sf{y + 7}

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\mapsto{ \sf{12 + 7}}

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