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3 years ago

14

A recipe uses 21/4 cups flour for a batch of cookies.Henry makes 10 batches of cookies for the bake sale. How many cups of flour

does Henry use?

1 answer:

gulaghasi [49]3 years ago

8 0

If you are using 2.25 cups for each batch and there are 10 batches. He would use 22 1/2 cups of flour for the cookies.

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Consider the first month's sales data for the Midwest region.

myrzilka [38]

Answer:

1. Significantly different from

1. Inconsistent

Step-by-step explanation:

Midwest region total stores equal to 63.1%. The percentage for current store is less than total stores therefore data in the given table is not consistent. The data given is relatively for the first month sales and is significantly different from the other stores.

8 0

3 years ago

Billy and I Angie are selling gift baskets at a craft fair their cost are $75 for the table and $12 per baskets they sell each b

dolphi86 [110]

20-12=8

8 divided by 75= 72

3 0

3 years ago

Read 2 more answers

Tablets are on sale for 15% off the original price (t), which can be expressed with the function p(t) = 0.85t. Local taxes are a

kolezko [41]

What its saying is that u have a discount price and that goes up by 8% so we know its not greater than 1

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3 years ago

Point V is on line segment UW, given VW = x + 7, UW = 3x - 9, and UV = 8, determine the numerical length of UW

krek1111 [17]

Answer:

The numerical length of UW is 27

Step-by-step explanation:

8 0

3 years ago

AYUDA CON ESTO!!! ALGUIEN PORFAVOR

Gre4nikov [31]

Answer:

Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

$Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds$

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

$\frac{200}{60} = \frac{10}{3} \approx 3.33$ loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

$\frac{200}{65} = \frac{40}{13} \approx 3.08$ loops per minute

then the period is:

$\frac{13}{40} =0.325\,\,\,minutes$

Therefore runner B has the smaller period

8 0

3 years ago