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Verdich [7]
3 years ago
11

Sam earned $5 on Monday, On each following day, through Friday, she earned 1 more dollar than the preceding day. What was the me

an earnings for the five day period, Monday through Friday?
Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0

Answer:

Step-by-step explanation:

(5+6+7+8+9)/5

35/5

7

So Sam averaged earning $7 per day

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You never actually asked a question but if you are asking the rate at which the football traveled then that would be traveling 1 foot down every 2.33333 seconds
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Amir solved the following equation. describe the first mistake he made.
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Answer:

he faked too much

Step-by-step explanation:

5 0
3 years ago
Jana is decorating 6 picture frames by gluing straws around the borders and adding wooden stars at the corners. Each picture fra
zzz [600]

Answer:

C: 48 straws

Step-by-step explanation:

First, find the perimeter of one picture frame: (2 x length) + (2 x width).  Convert 20 centimeters to millimeters so that you are working in the same units; there are 10 millimeters in 1 centimeter, so 20 centimeters = 200 millimeters.  

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Each picture frame has a perimeter of 640 millimeters.

Next, figure out how many straws are needed for one picture frame:

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Jana needs 48 straws to complete her project.

3 0
4 years ago
The coordinates of AB are A(-4,4) and B(2,1) which measurement is closest to the length of AB units
vredina [299]

Answer:

AB\approx 6.7\ units

Step-by-step explanation:

<u><em>Distance between two points:</em></u> Distance between two points (x_1,y_1)\ and\ (x_2,y_2) is given by

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2

A(-4,4)\ and\ B(2,1)\\\\AB=\sqrt{(1-4)^2+(2+4)^2}\\\\AB=\sqrt{(-3)^2+(6)^2}\\\\AB=\sqrt{45}\\\\AB=3\sqrt{5}\\\\AB\approx 6.7\ units

3 0
3 years ago
Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2
fredd [130]

Answer:

Both get the same results that is,

\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

Step-by-step explanation:

Given :

\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

and initial population,

\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]

a) - After two times, we will find in each position.

P_2=[P].[M]^2=[P].[M].[M]

M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]

     =\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]

b) - With in migration process, 500 people are numbered. There will be after a long time,

After\;inifinite\;period=[M]^n.[P]

Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]

                                   =\left[\begin{array}{ccc}140\\160\\200\end{array}\right]

4 0
3 years ago
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