Answer:
12:15 (simplified: 4:5)
12/15 (simplified: 4/5)
12 to 15 (simplified: 4 to 5)
Hope this helped!
Answer:
{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x
4
+4x
3
y+6x
2
y
2
+4xy
3
+y
4
Step-by-step explanation:
1 Use Square of Sum: {(a+b)}^{2}={a}^{2}+2ab+{b}^{2}(a+b)
2
=a
2
+2ab+b
2
.
({x}^{2}+2xy+{y}^{2})({x}^{2}+2xy+{y}^{2})(x
2
+2xy+y
2
)(x
2
+2xy+y
2
)
2 Expand by distributing sum groups.
{x}^{2}({x}^{2}+2xy+{y}^{2})+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x
2
(x
2
+2xy+y
2
)+2xy(x
2
+2xy+y
2
)+y
2
(x
2
+2xy+y
2
)
3 Expand by distributing terms.
{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2xy({x}^{2}+2xy+{y}^{2})+{y}^{2}({x}^{2}+2xy+{y}^{2})x
4
+2x
3
y+x
2
y
2
+2xy(x
2
+2xy+y
2
)+y
2
(x
2
+2xy+y
2
)
4 Expand by distributing terms.
{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}({x}^{2}+2xy+{y}^{2})x
4
+2x
3
y+x
2
y
2
+2x
3
y+4x
2
y
2
+2xy
3
+y
2
(x
2
+2xy+y
2
)
5 Expand by distributing terms.
{x}^{4}+2{x}^{3}y+{x}^{2}{y}^{2}+2{x}^{3}y+4{x}^{2}{y}^{2}+2x{y}^{3}+{y}^{2}{x}^{2}+2{y}^{3}x+{y}^{4}x
4
+2x
3
y+x
2
y
2
+2x
3
y+4x
2
y
2
+2xy
3
+y
2
x
2
+2y
3
x+y
4
6 Collect like terms.
{x}^{4}+(2{x}^{3}y+2{x}^{3}y)+({x}^{2}{y}^{2}+4{x}^{2}{y}^{2}+{x}^{2}{y}^{2})+(2x{y}^{3}+2x{y}^{3})+{y}^{4}x
4
+(2x
3
y+2x
3
y)+(x
2
y
2
+4x
2
y
2
+x
2
y
2
)+(2xy
3
+2xy
3
)+y
4
7 Simplify.
{x}^{4}+4{x}^{3}y+6{x}^{2}{y}^{2}+4x{y}^{3}+{y}^{4}x
4
+4x
3
y+6x
2
y
2
+4xy
3
+y
4
Answer:
slope is -2/5
Step-by-step explanation:
m=y2-y1/x2-x1
m=3-5/2-(-3))
m=-2/2+3
m=-2/5
Answer:
x is less than 4
or
x is greater than 4
Step-by-step explanation:
-5x < -15x + 40 -5x < -15x + 40
+15x +15x -40 -40
10x < 40 -40 - 5x < -15x
÷10 ÷10 +5x +5x
× < 4 -40 < -10x
÷10 ÷10
4 < ×
Answer:
A. y =
- 1
Step-by-step explanation:
Given parameters:
Equation of the line:
5x + 2y = 12
Coordinates = -2, 4
Unknown:
The equation of the line parallel to this line = ?
- To solve this problem, first, we need to find the slope of the given line.
Every linear equation have the formula: y = mx + c
m is the slope of the line, c is the y- intercept
5x + 2y = 12
Express this equation as y = mx + c
2y = -5x + 12
y =
+ 6
The slope of this line is 
- Now, any line that is parallel to another will not cut or cross it at any point. This simply implies they have the same slope.
Slope of the line parallel is 
- Our new line will also take the form y=mx + c,
Coordinates = -2, 4, x = -2 and y = 4
m is 
Now let us solve for C, the y-intercept;
4 = - 2 x
+ C
4 = 5 + C
C = -1
The equation of the line is therefore;
y =
- 1