An obtuse triangle is formed if there is an angle that has a measure of more than 90 degrees. You can determine if an obtuse angle is formed by two sides of a triangle if it meet this condition:
Let a and b be two sides of a triangle and c is the longest side:
So taking your given:
<
100 + 225 <
325 <
To get the smallest possible number, just get the square root of both sides:
<
18.03 < c
So your smallest possible whole number is 19
The area of the trapezoid would be 48
Let with X is denoted the length of the third side.
For a triangle the following statements must be true:
The sum<span> of the </span>lengths<span> of any two sides of a </span>triangle<span> is greater than the </span>length<span> of the third side.
This means that this inequality can be written: X<10+18 ,X<28
</span>
Answer:
- 1) y = (-2/3)x +2/3
- 2) y = (6/5)x -23/5
- 5) y = (-1/6)x +4/3
- 6) y = x -2
Step-by-step explanation:
A simple, mechanical way to do these (perpendicular lines) is ...
- replace any constant with 0
- swap the x- and y-coefficients, negating one
- for point (h, k), replace x with (x-h) and y with (y-k)
- solve for y (to get slope-intercept form)
1) 3x -2y = 0 . . . . . step 1
... 2x +3y = 0 . . . . step 2
... 2(x -1) +3(y -0) = 0 . . . . step 3
... 2x -2 = -3y . . . . eliminate parentheses, subtract 3y
... y = (-2/3)x +2/3 . . . . divide by the coefficient of y
2) 6(x -3) -5(y +1) = 0 . . . . after step 3
... 6x -23 = 5y . . . . . . . . . . simplify, add 5y
... y = (6/5)x - 23/5 . . . . . divide by the coefficient of y
5) (x+4) +6(y-2) = 0 . . . . . after step 3
... x -8 = -6y . . . . . . . . . . . simplify, subtract 6y
... y = (-1/6)x +4/3 . . . . . . divide by the coefficient of y
6) (y +5) = (x +3) . . . . . . . after step 3
... y = x -2 . . . . . . . . . . . . subtract 5
