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FromTheMoon [43]
3 years ago
8

Select the correct answer. Vincent wants to construct a regular hexagon inscribed in a circle. He draws a circle on a piece of p

aper. He then folds the paper circle three times to create three folds representing diameters of the circle. He labels the ends the diameters A, B, C, D, E, and F, and he uses a straightedge to draw the chords that form a hexagon. Which statement is true? A. Vincent’s construction method produces a hexagon that must be regular. B. Vincent’s construction method produces a hexagon that must be equilateral but may not be equiangular. C. Vincent’s construction method produces a hexagon that must be equiangular but may not be equilateral. D. Vincent’s construction method produces a hexagon that may not be equilateral and may not be equiangular.
Mathematics
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

B.

Step-by-step explanation:

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Answer yes or no to determine whether 102 is divisible by each number:
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Answer:

Step-by-step explanation:

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Read 2 more answers
In a right triangle, angle is an acute angle and sin angle = 4/9. Evaluate the other five trigonometric functions of angle.
kkurt [141]

Answer:

Part 1) cos(A)=\frac{\sqrt{65}}{9}

Part 2) tan(A)=4\frac{\sqrt{65}}{65}

Part 3) cot(A)=\frac{\sqrt{65}}{4}

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Step-by-step explanation:

Let

A------> the angle

we have that

sin(A)=\frac{4}{9}

step 1

Find the cos(A)

we know that

cos^{2}(A)+sin^{2}(A)=1

substitute the value of sin(A)

cos^{2}(A)+(\frac{4}{9})^{2}=1

cos^{2}(A)=1-(\frac{4}{9})^{2}

cos^{2}(A)=1-(\frac{16}{81})

cos^{2}(A)=(\frac{65}{81})

cos(A)=\frac{\sqrt{65}}{9}

step 2

Find the tan(A)

we know that

tan(A)=\frac{sin(A)}{cos(A)}

substitute the values

tan(A)=\frac{\frac{4}{9}}{\frac{\sqrt{65}}{9}}

tan(A)=\frac{4}{\sqrt{65}}

tan(A)=4\frac{\sqrt{65}}{65}

step 3

Find the cot(A)

we know that

cot(A)=\frac{1}{tan(A)}

we have

tan(A)=\frac{4}{\sqrt{65}}

substitute

cot(A)=\frac{1}{\frac{4}{\sqrt{65}}}

cot(A)=\frac{\sqrt{65}}{4}

step 4

Find the sec(A)

we know that

sec(A)=\frac{1}{cos(A)}

we have

cos(A)=\frac{\sqrt{65}}{9}

substitute

sec(A)=\frac{1}{\frac{\sqrt{65}}{9}}

sec(A)=\frac{9}{\sqrt{65}}

sec(A)=9\frac{\sqrt{65}}{65}

step 5

Find the csc(A)

we know that

csc(A)=\frac{1}{sin(A)}

we have

sin(A)=\frac{4}{9}

substitute the value

csc(A)=\frac{1}{\frac{4}{9}}

csc(A)=\frac{9}{4}

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