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zzz [600]
3 years ago
11

Samuel bout 3x cds and jayce bought 2x - 1 cd's if each had a regular price of $18 and discount of $2

Mathematics
1 answer:
Semmy [17]3 years ago
3 0

Answer:

2(5x-1)

Step-by-step explanation:

Given that;

Samuel bought 3x cds

jayce bought 2x-1 cds

Note that the total number of cd :

3x cds + 2x - 1 cd's

3x+(2x-1) = 3x+2x-1

= 5x-1

To get the amount to f cds on discount

= Total amount of cds multiply by the discounted price

= (5x-1)×$2

= 2(5x-1)

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Ksivusya [100]

Answer:

beforehand and her bank statement

Step-by-step explanation:

For Barbara to reconcile her bank statement, she needs to calculate beforehand and look for when she can get her bank statement.  If she needs to reconcile her bank account, Barbara will measure and check for her running balance. However, the bank reconciliation statement is very relevant because it shows an account's cash balance automatically as already subtracted by the reconciliation element.

3 0
3 years ago
Mr. hill had 471 pencils. He gave away 164 pencils. How many pencils did he keep
dimulka [17.4K]

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3 0
3 years ago
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In the Stone Ridge apartment complex 35% of the apartments have one bedroom if there are 49 one bedroom apartments what is the t
Softa [21]

Answer:

140

Step-by-step explanation:

Given:

In the Stone Ridge apartment complex 35% of the apartments have one bedroom.

If there are 49 one bedroom apartments.

Question asked:

What is the total number of apartments at Stone ridge ?

Solution:

<u>Let total number of apartments at Stone ridge</u> = x

Now according to question:

35% of the total apartments having one bedroom = 49

35\%\ of x = 49

\frac{35}{100}\times x = 49

\frac{35x}{100} = 49

By cross multiplication:

35x = 49\times100\\35x= 4900\\

By dividing both sides by 35

\frac{35x}{35} = \frac{4900}{35} \\x = 140

Therefore, total number of apartments at Stone ridge is 140

4 0
3 years ago
Solve: 64^-3x-3 * 64+22=38<br> a. x= - 9/8<br> b. x= - 8/9<br> c. x= 8/9<br> d. x= 9/8
Paha777 [63]

Answer:

it is <em><u>B</u></em>

hope i helped

if you can give me brainliest that would be great

8 0
4 years ago
Are there concepts/processes to strictly follow in writing radicals as expressions with rational exponents?
Eva8 [605]

Answer:

The concept or process is x^{\frac{m}{n}}=(\sqrt[n]{x})^m.

Step-by-step explanation:

Consider the provided information.

The following property can be used to rewrite each radical as an exponent.

The numerator tells the power of the resulting rational exponent, and the denominator of the rational exponents tells the root of that number.

x^{\frac{m}{n}}=(\sqrt[n]{x})^m

For example:

(27)^{\frac{2}{3}}=(\sqrt[3]{27})^2

(27)^{\frac{2}{3}}=(3)^2

(27)^{\frac{2}{3}}=9

Hence, the concept or process is x^{\frac{m}{n}}=(\sqrt[n]{x})^m.

5 0
3 years ago
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