This problem is about adding up the surface area of all of the surfaces he will paint and then dividing it by 200 to find how many gallons he will need to buy. Since he won't paint his roof, we need to find the surface area of every square foot that he will paint. So to do this it is just doing the area formula A=L*W for rectangles, and A=1/2*H*W, for the triangles. So he will paint 2 triangular spaces, the front and the back, plus he will paint 4 rectangular walls. So let's do the very front section first. When looking straight at the front u see a rectangle and a triangle. So let's find the area of both. The rectangle we need to plug in the length, or in other words the height, which is 8 feet. The width is 12 ft. So what is 8 times 12? It is 96 sq. ft. So 96 square feet is the front rectangle. There is another rectangle on the back of the shed that's the same dimensions that he will paint, so instead of doing that again we can just multiply 96 sq ft by 2, which is 192 sq ft. Now let's do the 2 triangles he will paint. Both of the triangles are the same exact dimensions, so what we do is plug the numbers in, the height is 4 ft. So it looks like 1/2 * 4 ft * 12 ft. 1/2 of 4 is 2, so multiply 2 by 12, which equals 24. So one of the triangles has 24 sq ft, but since there is another one on the back side that he will paint, we multiply that by 2 to save time. This will equal 48 sq ft. Now all we have to do is the other two walls on the sides. This is the same formula, A= L*W. so length is the same as the other 2 rectangles because they are the same height, so the length is 8 ft. And the width is 20 ft. What is 20 times 8? 20 times 8 is 160 sq ft. Since there is another wall just like that on the other side, we multiply that by 2 to get 320 sq ft. Now we add all of it up. 320+ 48+ 192= 560 sq ft. So he will paint 560 sq ft. What is 560 divided by 200? It will be 2.8, so he will have to buy 2.8 gallons of paint. Since you can't buy 2.8 gallons of paint, he will really buy 3 gallons, so he will have some left over. Since 1 gallon cost $48, we will need to multiply 48 by 3, to give us 144. So he will spend $144 on paint to paint his shed. I hope this helps
Answer:
Part c: Contained within the explanation
Part b: gcd(1200,560)=80
Part a: q=-6 r=1
Step-by-step explanation:
I will start with c and work my way up:
Part c:
Proof:
We want to shoe that bL=a+c for some integer L given:
bM=a for some integer M and bK=c for some integer K.
If a=bM and c=bK,
then a+c=bM+bK.
a+c=bM+bK
a+c=b(M+K) by factoring using distributive property
Now we have what we wanted to prove since integers are closed under addition. M+K is an integer since M and K are integers.
So L=M+K in bL=a+c.
We have shown b|(a+c) given b|a and b|c.
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Part b:
We are going to use Euclidean's Algorithm.
Start with bigger number and see how much smaller number goes into it:
1200=2(560)+80
560=80(7)
This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.
Part a:
Find q and r such that:
-65=q(11)+r
We want to find q and r such that they satisfy the division algorithm.
r is suppose to be a positive integer less than 11.
So q=-6 gives:
-65=(-6)(11)+r
-65=-66+r
So r=1 since r=-65+66.
So q=-6 while r=1.
Answer:
Looking at the first question, it's asking what best describes the probability of tossing a number less than 6 on a number cube that has 6 numbers. Impossible means that it will never land on it, for example asking what the probability of landing on 7 is. Unlikely is something that doesn't happen often. The best option that fits our scenario is option C, likely.
Looking at the second question, it's asking what the probability that the teacher chooses a girl in his class. There are 15 girls and a total of 27 students in the class so we take the probability by doing 15/27. We can narrow both the numerator and the denominator using 3 which gives us 5/9. Therefore, the best option that fits our scenario is option C, 5/9.
Finally, looking at the last question, it's asking what the theoretical probability that the coin will land on heads on the next toss. Theoretical probability doesn't consider how much times Murray tossed the coin, the only thing it cares about is what the actual probability of tossing a coin is. Therefore that makes it a 50% chance of landing on a heads and a 50% chance of landing on a tails. The best option that first our scenario is option B, 1/2.
<u><em>Hope this helps! Let me know if you have any questions</em></u>
Answer: 67.5
Step-by-step explanation:
