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koban [17]
2 years ago
8

During summer vacation, the Barton family drove from California to Oklahoma. While on their trip they noticed the cost of gasoli

ne per gallon varied.
Cost of Gasoline
Per Gallon
$2.88
$3.24
$2.88
$2.90
$2.79
$3.79
What was the mean cost of gasoline per gallon?
$2.88
$2.79
$2.89
$3.08
Mathematics
1 answer:
Talja [164]2 years ago
4 0

Answer:

3.08

Step-by-step explanation:

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How many people like 2 kinds of dancing but not all 3 kinds of dancing?
marshall27 [118]

Answer:

38 people

Step-by-step explanation:

add 11, 18, and 9 together

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3 years ago
What is the answer to 90 is 45% of what?
ANTONII [103]
..... 40.5 ...............
7 0
3 years ago
Read 2 more answers
What is the equation of a line that contains the point (6,-4) and has a slope of 3/4?
elixir [45]

Answer:

B. y+ 4 = 3/4 (x-6)

Step-by-step explanation:

Given:

m = 3/4

Slope-intercept:

y - y1 = m(x - x1)

y + 4 = 3/4(x - 6)

3 0
3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
son4ous [18]

one angle is 3x-3

another angle is 6(x-10)

Both angles are vertically opposite angles

Vertically opposite angles are always equal

So we equation both the angles and solve for x

3x - 3= 6(x-10)

3x - 3 = 6x - 60

Subtract 6x from both sides

-3x - 3 = -60

Add 3 on both sides

-3x = -57

Divide by 3

x = 19

The value of x= 19


3 0
3 years ago
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