This a pretty typical right triangle trig problem; the first step is to figure out what we have and what we want in relation to an acute angle in the problem.
Here we have a right triangle, G=90°, and we're given angle F=23°. So we have to name everything in relation to F.
31 = FG is <em>adjacent </em>to F.
x = GE is <em>opposite </em>to F.
OK, we have an opposite and adjacent; that tells us we need to use the tangent of F. Let's write it:
tan 23° = tan F = opp/adj = x/31
Solving,
x = 31 tan 23°
I hate the calculator part. I used to love that part.
x = 31 tan 23° ≈ 13.16 feet
Answer: 4) x ≈ 13.2 ft
Answer:
Step-by-step explanation:
So we cant go over $250
35+20n=250
now that i put the question in an expression we can take the 35 away from both sides
35+20n=250
-35. -35
_____________
20n=215
now divide 20 by both sides to get (n) alone
20n=215
________
20
n= 10.75
we round down because we cannot exceed the limit, thus
ANSWER: 10 months
9514 1404 393
Answer:
A, M, N, F
Step-by-step explanation:
I find it easier to look at the graph, rather than mess with the coordinate transformations. Each image point is the same distance from the line of reflection that its pre-image point is. The line joining the two points is perpendicular to the line of reflection.
See attached for the reflected points.
__
The red and turquoise dashed lines are the lines y=x and y=-x, respectively. The same-colored arrows show the reflection of the relevant point.
_____
The transformations of interest are ...
(x, y) ⇒ (y, x) . . . . reflection over y = x
(x, y) ⇒ (-x, y) . . . . reflection over y-axis
(x, y) ⇒ (x, -y) . . . . reflection over x-axis
(x, y) ⇒ (-y, -x) . . . . reflection over y = -x
