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kifflom [539]
3 years ago
11

Consider f(x)=sin(x) and g(x)=f(x+pi)-3

Mathematics
1 answer:
Daniel [21]3 years ago
6 0

Find the point (x, y) on the unit circle that corresponds to the real number t. ... sketch the graph of the function. (In. 26. f(x) = 3− 2sinπx. 27. g(x) = 1. 2 tan x − π. 2.
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Which expression is equivalent to (sf)(6)
SashulF [63]

Answer:

(st)(6)= s(6) * t(6)

Step-by-step explanation:

(st)(6)

(st)(x)= s(x) * t(x) we multiply it

(st)(6)= s(6) * t(6)

Hope this helps.

4 0
2 years ago
The first term in a sequence is 3<br> The term-to-term rule is + 8<br> What is the 5th term?
galben [10]
2nd term: 3+8
= 11
3rd term: 11+8
= 19
4th term: 19+8
= 27
5th term: 27+8
= 35


OR
((n-1)x8)+3
7 0
2 years ago
I'm looking at the top at 79.9 angle. I'm 100ft away. What's the height of the building?
Anni [7]
To solve this, notice that you have the angle component (I will call this a) and the x-component (the distance of you from the building) of a trig formula, and you are looking for the y-component. We will use the tangent formula, since this incorporates the angle, x, and y components.

1. Write the formula

tan(a) = y ÷ x

2. Rewrite to include the known values.

tan(79.9) = y ÷ 100

3. Solve for the unknown variable, y.

tan(79.9) × 100 = y ÷ 100 × 100

tan(79.9) × 100 = y

4. A fancy step that I call the "flip flop."

y = tan(79.9) × 100

5. Use a calculator to find the value (make sure the calculator is in "degree" and not "radians" mode).

y = 561.3968

6. Round the number as is appropriate for this problem.

Have a great day!

7 0
3 years ago
Read 2 more answers
Each day Lexi recorded the height of a plant for her science lab. The plant was 2.5 centimeters when planted and grew at a rate
g100num [7]
Here’s the answer w the steps :)

7 0
3 years ago
31. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.
Whitepunk [10]

Answer:

The required linear equation satisfying the given conditions f(-1)=4 and f(5)=1 is $y=\frac{-1}{2} x+\frac{7}{2}$

Step-by-step explanation:

It is given that f(-1)=4 and f(5)=1.

It is required to find out a linear equation satisfying the conditions f(-1)=4

and f(5)=1. linear equation of the line in the form

$$\left(y-y_{2}\right)=m\left(x-x_{2}\right)$$

Step 1 of 4

Observe, f(-1)=4 gives the point (-1,4)

And f(5)=1 gives the point (5,1).

This means that the function f(x) satisfies the points (-1,4) and (5,1).

Step 2 of 4

Now find out the slope of a line passing through the points (-1,4) and (5,1),

$$\begin{aligned}&m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\&m=\frac{1-4}{5-(-1)} \\&m=\frac{-3}{5+1} \\&m=\frac{-3}{6} \\&m=\frac{-1}{2}\end{aligned}$$

Step 3 of 4

Now use the slope $m=\frac{-1}{2}$ and use one of the two given points and write the equation in point-slope form:

$(y-1)=\frac{-1}{2}(x-5)$

Distribute $\frac{-1}{2}$,

$y-1=\frac{-1}{2} x+\frac{5}{2}$

Step 4 of 4

This linear function can be written in the slope-intercept form by adding 1 on both sides,

$$\begin{aligned}&y-1+1=\frac{-1}{2} x+\frac{5}{2}+1 \\&y=\frac{-1}{2} x+\frac{5}{2}+\frac{2}{2} \\&y=\frac{-1}{2} x+\frac{7}{2}\end{aligned}$$

So, this is the required linear equation.

8 0
2 years ago
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