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morpeh [17]
3 years ago
10

Find l of the following cone ​

Mathematics
2 answers:
e-lub [12.9K]3 years ago
8 0

Answer:

l =  \sqrt{261}\: in

Step-by-step explanation:

Height of the cone h = 15 in

Radius of the cone r = 12/2 = 6 in

We need to find slant height (l) =?

\because l =  \sqrt{ {r}^{2}  +  {h}^{2} }  \\  \\ \therefore l =  \sqrt{ {6}^{2} +  {15}^{2}  }  \\  \\\therefore  l =  \sqrt{36 + 225}  \\  \\\therefore  l =  \sqrt{261}  \\

andrey2020 [161]3 years ago
6 0

Answer:

l = √261 in

Step-by-step explanation:

Hope this helps

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Her total should be 84. You have your 30 dollars that will not change which you need to add to the amount of every visit. To find the amount for each time she went you have to do 3*18 because she went 18 times for 3 dollars each. Your answer to 3*18 should be 54. You now have to add those 54 to the 30 per month. 30+54. That should be 84
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what is the median number of car show this month Frank 25, Sarah 20, randall 15, Brahim 22, Alice 20,
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Step-by-step explanation:

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4 0
3 years ago
(2*)2-3×2*+2=0<br>4m-15°(×)m+75°​
Valentin [98]

Answer:

First, we write the augmented matrix.

⎡

⎢

⎣

1

−

1

1

2

3

−

1

3

−

2

−

9

|

8

−

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⎤

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⎦

Next, we perform row operations to obtain row-echelon form.

−

2

R

1

+

R

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=

R

2

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

3

−

2

−

9

|

8

−

18

9

⎤

⎥

⎦

−

3

R

1

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

0

1

−

12

|

8

−

18

−

15

⎤

⎥

⎦

The easiest way to obtain a 1 in row 2 of column 1 is to interchange \displaystyle {R}_{2}R

​2

​​  and \displaystyle {R}_{3}R

​3

​​ .

Interchange

R

2

and

R

3

→

⎡

⎢

⎣

1

−

1

1

8

0

1

−

12

−

15

0

5

−

3

−

18

⎤

⎥

⎦

Then

−

5

R

2

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

57

|

8

−

15

57

⎤

⎥

⎦

−

1

57

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

1

|

8

−

15

1

⎤

⎥

⎦

The last matrix represents the equivalent system.

x

−

y

+

z

=

8

y

−

12

z

=

−

15

z

=

1

Using back-substitution, we obtain the solution as \displaystyle \left(4,-3,1\right)(4,−3,1).First, we write the augmented matrix.

⎡

⎢

⎣

1

−

1

1

2

3

−

1

3

−

2

−

9

|

8

−

2

9

⎤

⎥

⎦

Next, we perform row operations to obtain row-echelon form.

−

2

R

1

+

R

2

=

R

2

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

3

−

2

−

9

|

8

−

18

9

⎤

⎥

⎦

−

3

R

1

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

5

−

3

0

1

−

12

|

8

−

18

−

15

⎤

⎥

⎦

The easiest way to obtain a 1 in row 2 of column 1 is to interchange \displaystyle {R}_{2}R

​2

​​  and \displaystyle {R}_{3}R

​3

​​ .

Interchange

R

2

and

R

3

→

⎡

⎢

⎣

1

−

1

1

8

0

1

−

12

−

15

0

5

−

3

−

18

⎤

⎥

⎦

Then

−

5

R

2

+

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

57

|

8

−

15

57

⎤

⎥

⎦

−

1

57

R

3

=

R

3

→

⎡

⎢

⎣

1

−

1

1

0

1

−

12

0

0

1

|

8

−

15

1

⎤

⎥

⎦

The last matrix represents the equivalent system.

x

−

y

+

z

=

8

y

−

12

z

=

−

15

z=1

Using back-substitution, we obtain the solution as \displaystyle \left(4,-3,1\right)(4,−3,1).

7 0
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Step-by-step explanation:

Process

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    csc Ф = \frac{hypotenuse}{opposite side}

    csc Ф = \frac{5}{-4}  = \frac{-5}{4}

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Lesechka [4]

Answer:

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It took 3 hours for her to deliver 189 total.

We need delivery per hour for our answer.

189 / 3 = 63

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8 0
3 years ago
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