The anwser is c your welcome
Answer:
9000 ft
Step-by-step explanation:
Given: A airplane is ascending at a constant rate of 15 feet per second,
What we need to know: The change in altitude during 10 minutes of flight,
60 seconds = 1 minute
60 × 10
= 600 seconds
600 × 15
= 9000 ft
Therefore there was a 9000 ft change in altitude during the 10 minutes of the flight.
Answer:
the correct answer is Y=-x-3
Answer:
The daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.
Step-by-step explanation:
Since to rent a car, a person is charged a daily rate and a fee for each kilometer driven, and when Chena rented a car for 6 days and drove 320 km, the charge was $ 286.00, while when she rented the same car for 10 days and drove 900 km, the charge was $ 605.00, to determine the daily rate and the fee for each kilometer driven the following calculation must be performed:
286 = 6 days and 320 km
320/6 = 53,333 km
286/6 = $ 47,666
Thus, the value of 1 day and 53,333 km is $ 47,666.
605 = 10 days and 900 km
900/10 = 90 km
605/10 = $ 60.5
Thus, the value of 1 day and 90 km is $ 60.5.
90 - 53,333 = 36,666
60.5 - 47.666 = 12.833
12,833 / 36,666 = value per kilometer traveled
0.35 = value per kilometer traveled
(286 - (0.35 x 320)) / 6 = X
(286/112) / 6 = X
174/6 = X
29 = X
(605 - (0.35 x 900)) / 10 = X
(605 - 315) / 10 = X
290/10 = X
29 = X
Therefore, the daily rate is $ 29 and the fee for each kilometer driven is $ 0.35.
Answer:
the numbers are 20, 21 and 22
Step-by-step explanation:
x+(x+1) + (x+2) = 63
3x +3 = 63
3x = 60
x = 20
doing this for ponits
