Answer:
Rhombic sulphur and monoclinic sulphur.
We are given the pOH of the solution of 10.75. pOH is the property of the solution that is related to the OH ion concentration of the solution. THe formula to be followed is pOH = -log (OH); OH- = 10^-pOH. In this case, OH- = 10^-10.75 equal to B. 1.778 x 10^-11 M
Telling the teacher about a chemical spill immediately
Answer:
The mass of radon that decompose = 63. 4 g
Explanation:
R.R = P.E/(2ᵇ/ⁿ)
Where R.R = radioactive remain, P.E = parent element, b = Time, n = half life.
Where P.E = 100 g , b = 5.55 days, n = 3.823 days.
∴ R.R = 100/
R.R = 100/
R.R = 100/2.73
R.R = 36.63 g.
The mass of radon that decompose = Initial mass of radon - Remaining mass of radon after radioactivity.
Mass of radon that decompose = 100 - 36.63
= 63.37 ≈ 63.4 g
The mass of radon that decompose = 63. 4 g
<u>Answer:</u> The volume of given mas of tin block at STP is 
<u>Explanation:</u>
To calculate volume of of the substance, we use the equation:

We are given:
Mass of tin = 95.04 g
Density of tin = 
Putting values in above equation, we get:

Hence, the volume of given mas of tin block at STP is 