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3 years ago

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Consider a balloon that has a volume V. It contains n moles of gas, it has an internal pressure of P, and its temperature is T.

If the balloon is heated to a temperature of 15.5T while it is placed under a high pressure of 15.5P, how does the volume of the balloon change?

2 answers:

Dmitry [639]3 years ago

6 0

B.) it stays the same

eduard3 years ago

4 0

Answer: The temperature will not change and will remain T.

Explanation: Accoding to ideal gas law:

$PV=nRT$

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = Gas constant = 0.0821 Latm/moleK

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$P_1$ = initial pressure

$V_1$ = initial volume

$T_1$ = initial temperature

$P_2$ = final pressure

$V_2$ = final volume

$T_2$ = final temperature

Putting in the values:

$\frac{PV}{T}=\frac{15.5PV_2}{15.5T}$

$T_2=T$

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