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g100num [7]
3 years ago
13

Consider a balloon that has a volume V. It contains n moles of gas, it has an internal pressure of P, and its temperature is T.

If the balloon is heated to a temperature of 15.5T while it is placed under a high pressure of 15.5P, how does the volume of the balloon change?
Chemistry
2 answers:
Dmitry [639]3 years ago
6 0
B.) it stays the same
eduard3 years ago
4 0

Answer: The temperature will not change and will remain T.

Explanation: Accoding to ideal gas law:

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = Gas constant = 0.0821 Latm/moleK

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

P_1= initial pressure

V_1= initial volume

T_1= initial temperature

P_2= final pressure

V_2= final volume

T_2= final temperature

Putting in the values:

\frac{PV}{T}=\frac{15.5PV_2}{15.5T}

T_2=T

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Arrange the molecules in order from strongest intermolecular force to weakest.
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A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.692 kg of water
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Answer:

494.49 g of NaCl.

Explanation:

Data obtained from the question include the following:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mass of NaCl =.?

Next, we shall determine the number of mole of NaCl in the solution.

Molality is simply defined as the mole of solute per unit kilogram of solvent. Mathematically, it is expressed as

Molality = mole of solute /Kg of solvent

With the above formula, we can obtain the number of mole NaCl in the solution as follow:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mole of NaCl =..?

Molality = mole of solute /Kg of solvent

3.140 = mole of NaCl /2.692

Cross multiply

Mole of NaCl = 3.140 x 2.692

Mole of NaCl = 8.45288 moles

Finally, we shall covert 8.45288 moles of NaCl to grams. This can be obtained as follow:

Mole of NaCl = 8.45288 moles

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

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Mole = mass /Molar mass

8.45288 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 8.45288 × 58.5

Mass of NaCl = 494.49 g.

Therefore, 494.49 g of NaCl are present in the solution.

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3 years ago
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