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g100num [7]
3 years ago
13

Consider a balloon that has a volume V. It contains n moles of gas, it has an internal pressure of P, and its temperature is T.

If the balloon is heated to a temperature of 15.5T while it is placed under a high pressure of 15.5P, how does the volume of the balloon change?
Chemistry
2 answers:
Dmitry [639]3 years ago
6 0
B.) it stays the same
eduard3 years ago
4 0

Answer: The temperature will not change and will remain T.

Explanation: Accoding to ideal gas law:

PV=nRT

where,

P = pressure of the gas

V = volume of the gas

T = temperature of the gas

n = number of moles of gas

R = Gas constant = 0.0821 Latm/moleK

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

P_1= initial pressure

V_1= initial volume

T_1= initial temperature

P_2= final pressure

V_2= final volume

T_2= final temperature

Putting in the values:

\frac{PV}{T}=\frac{15.5PV_2}{15.5T}

T_2=T

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A whole number, not a fraction, that can be negative, positive or zero are integers. They cannot have decimal places.

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yuradex [85]

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7 0
1 year ago
When KNO3 dissolved in water, what is the intermolecular attraction between NO3 ions
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2 years ago
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