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3 years ago

De dónde se obtienen los datos generales complementarios que se utilizan para calcular la razones de actividad

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

8 0

Answer:

En el departamento de ventas.

Explicación paso a paso:

Los datos generales complementarios se pueden obtener del departamento de ventas donde están presentes los datos sobre ventas y nos ayudan a calcular los ratios de actividad. El índice de actividad se puede calcular dividiendo las ventas de la empresa por sus activos totales. Este índice de actividad indica la eficiencia de una empresa mediante el uso de sus activos disponibles para producir ventas. El índice de actividad también se denomina "Índice de gestión de activos". Los datos de ventas son necesarios para el índice de actividad que puede estar disponible en el departamento de ventas.

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One technique that you can apply when solving such a problem is trial and error. We try to use each equation to prove that a given value of x on the table given will correspond to the value of y on the table.

a) Let's try to put x = 3 for the first equation and we must get an answer equal to 2.25.

$y=7.72(3)-29.02=-5.86_{}$

Since the value of y is not equal to 2.25 and the deviation is too large. this equation is not a good model,

b) We put x = 3 on the second equation and solve for y

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Since the value of y is not equal to 2.25 and the deviation is too large. this equation is not a good model,

c) We put x = 3 on the third equation and solve for y,

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Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of x. If x = 5, we get

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which has a slight deviation on the given value of y on the table for x = 5. let's try for x = 7. We have

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$\begin{gathered} y=0.4(8)^2+0.79(8)-4.93=26.99 \\ y=0.4(12)^2+0.79(12)-4.93=62.15 \\ y=0.4(14)^2+0.79(14)-4.93=84.53 \end{gathered}$

And as you can see, the deviation of values from the table to calculated becomes smaller. Hence, this is the best model.

d) We put x = 3 on the third equation and solve for y,

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Again, the value that we get is not equal to 2.25, hence, this equation is not a good model. But since its value is close to 2.25, we try to other values of x. If x = 5, we get

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Based on the calculations used above, the best equation that can be a good model is equation 3.

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1 year ago

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jeka94

Answer:

Step-by-step explanation:

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4 years ago