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pychu [463]
3 years ago
9

Which of these statements are true for joint variations? Check all that apply.

Mathematics
1 answer:
Fudgin [204]3 years ago
8 0

Answer:

B and C

Step-by-step explanation:

Just did it on edg

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700, 1200, 1600, 2000, X
Savatey [412]

Answer:

2500

Step-by-step explanation:

The mean of 700, 1200, 1600, 2000, 2500 is 1600.

5 0
2 years ago
to pass a math test, students must orrectly answer at least 0.6 of the questions Donald's schore is 5/8 karen's score is 0.88 gi
Anna11 [10]

Answer:

If a passing score is equal to or greater than 0.6, then all four students passed the test.

Step-by-step explanation:

6 0
2 years ago
At what rates did she invest?<br> $1500 invested at___%<br> $800 invested at ____%
frosja888 [35]

Answer:

4% and 5% respectively

Step-by-step explanation:

Let the intrest rate be x in the first account at x% and (x+1)% in the second account.

ATQ, 100=(x)*1500/100+(x+1)*800/100

x=4.

3 0
2 years ago
If you wanted to make the graph of y = 6*+7
dangina [55]

you would put the first point on (0,7) because that is the y intercept and then you would go up 6 and right one and then plot the next point assuming it is *6x + 7.

7 0
3 years ago
I need help , if yk the answer help fr!!!
Feliz [49]

Answer:

The measure of the angle JKG is:

m∠JKG = 56°

Step-by-step explanation:

<u>Given</u>

m∠JKG = 76-2x

m∠FHK = 6x-4

J is a midpoint of the segment FG and K is a midpoint of the segment GH.

<u>To determine</u>

m∠JKG = ?

Given that J is a midpoint of the segment FG and K is a midpoint of the segment GH. Thus, making two similar triangles, ΔJGK and ΔFGH

We know that two triangles are similar if the only difference is size. So, the angles remain the same.

so m∠JKG and m∠FHK are equal.

i.e.

m∠JKG = m∠FHK

substitute m∠JKG = 76-2x and m∠FHK = 6x-4

76-2x = 6x-4

6x+2x = 76 + 4

8x = 80

divide both sides by 8

8x/8 = 80/8

x = 10

Therefore, the value of x = 10

As

m∠JKG = 76-2x

substitute x = 10

m∠JKG = 76 - 2(10)

             = 76 - 20

             = 56°

Therefore, measure of the angle JKG is:

m∠JKG = 56°

4 0
2 years ago
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