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xxMikexx [17]
2 years ago
5

BRAINLIEST IF CORRECT i really need help to keep my grade up

Mathematics
1 answer:
mario62 [17]2 years ago
3 0

Answer:

48/12, 64/16, 4/1

Step-by-step explanation:

1. 16/4 x 3/3 = 48/12

2. 16/4 x 4/4 = 64/16

3. 16/4 ÷ 4/4 = 4/1

You might be interested in
Is 8(a+b) and (6a+3b)+2b equivalent
miv72 [106K]

Answer:

no

Step-by-step explanation:

8a+8b are not equivalent 6a+5b

5 0
3 years ago
How do you do these questions?
Lady bird [3.3K]

Answer:

(e) csc x − cot x − ln(1 + cos x) + C

(c) 0

Step-by-step explanation:

(e) ∫ (1 + sin x) / (1 + cos x) dx

Split the integral.

∫ 1 / (1 + cos x) dx + ∫ sin x / (1 + cos x) dx

Multiply top and bottom of first integral by the conjugate, 1 − cos x.

∫ (1 − cos x) / (1 − cos²x) dx + ∫ sin x / (1 + cos x) dx

Pythagorean identity.

∫ (1 − cos x) / (sin²x) dx + ∫ sin x / (1 + cos x) dx

Divide.

∫ (csc²x − cot x csc x) dx + ∫ sin x / (1 + cos x) dx

Integrate.

csc x − cot x − ln(1 + cos x) + C

(c) ∫₋₇⁷ erf(x) dx

= ∫₋₇⁰ erf(x) dx + ∫₀⁷ erf(x) dx

The error function is odd (erf(-x) = -erf(x)), so:

= -∫₀⁷ erf(x) dx + ∫₀⁷ erf(x) dx

= 0

7 0
3 years ago
George buys some first class and second class stamps to put on some letters. Each first class stamp costs 67p, and each second c
Dafna1 [17]

Answer:

£191.36

Step-by-step explanation:

Sum the parts of the ratio, 1 + 4 = 5 parts

Divide 320 by 5 to find the value of one part of the ratio.

320 ÷ 5 = 64 ← value of 1 part of the ratio , thus

4 parts = 4 × 64 = 256

Thus he bought 64 first class and 256 second class.

Cost = (64 × £0.67) + (256 × £0.58)

        = £42.88 + 148.48

        = £191.36

3 0
3 years ago
Please help me with 16-18 ty!!
jonny [76]

16: B; irrational number, real

17: C; whole, integer, rational, real

18: B; real, rational, integer

3 0
3 years ago
During a science experiment,the temperature of a solution in beaker 1 was 5 degrees below zero. The temperature of a solution in
GaryK [48]
Answer:
5 degrees

Step-by-step explanation:

We are given that during a science experiment
The temperature of a solution in a beaker 15 degrees below zero
The temperature of solution in a beaker 2 was opposite of the temperature in beaker 1
We have to determine the temperature of beaker 2.
It mean temperature of beaker 1 solution=-5 degrees
According to question
Temperature of beaker 2 solution =5 degrees
Hence, the temperature of solution in a beaker 2=5 degrees
7 0
1 year ago
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